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trapecia [35]
2 years ago
10

If

Mathematics
1 answer:
Greeley [361]2 years ago
4 0

Answer:i dont know

Step-by-step explanation:

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How many square inches are 9 cubes with a 1 inch edge
ki77a [65]
Add it up then you will get answer

4 0
3 years ago
Solve 4(x + 6) = 2(2x + 12)
Andru [333]

Answer:

Infinitely many solutions

Step-by-step explanation:

4(x+6)=2(2x+12)

4(x+6)=2(2(x+6))

4(x+6)=4(x+6)

Infinitely many solutions

3 0
2 years ago
Read 2 more answers
Find the surface area S of the following cylinder.
Tanya [424]

Answer:

384π

Step-by-step explanation:

From the diagram,

Diameter ( d ) = 16

Height ( h ) = 16

To find : Surface area of Cylinder = ?

Radius ( r ) = ?

Formula : -

r = d / 2

r = 16 / 2

r = 8

Formula : -

Surface area of Cylinder = 2πr ( r + h )

Surface area of Cylinder = 2πr ( r + h )

= 2π x 8 ( 8 + 16 )

= 16π x 24

Surface area of Cylinder = 384π

4 0
3 years ago
What is the IQR (interquartile range) of the data set? 33, 37, 45, 61, 64, 67
Nataly_w [17]

solution is first os all find median

median is( 45+61)/2=53

find median of no in left of 53

it is 37

find median of no in right of 53

it is 64

now interquartile range=64-53=27

4 0
3 years ago
At a local university, a sample of 49 evening students was selected in order to determine whether the average age of the evening
pav-90 [236]

Answer:

z=\frac{23-21}{\frac{3.5}{\sqrt{49}}}=4    

p_v =2*P(z>4)=0.0000633  

When we compare the significance level \alpha=0.1 we see that p_v so we can reject the null hypothesis at 10% of significance. So the  the true mean is difference from 21 at this significance level.

Step-by-step explanation:

Data given and notation  

\bar X=23 represent the sample mean

\sigma=3.5 represent the population standard deviation

n=49 sample size  

\mu_o =21 represent the value that we want to test

\alpha=0.1 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the average age of the evening students is significantly different from 21, the system of hypothesis would be:  

Null hypothesis:\mu = 21  

Alternative hypothesis:\mu \neq 21  

The statistic is given by:

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

Calculate the statistic

We can replace in formula (1) the info given like this:  

z=\frac{23-21}{\frac{3.5}{\sqrt{49}}}=4    

P-value

Since is a two sided test the p value would be:  

p_v =2*P(z>4)=0.0000633  

Conclusion  

When we compare the significance level \alpha=0.1 we see that p_v so we can reject the null hypothesis at 10% of significance. So the  the true mean is difference from 21 at this significance level.

8 0
3 years ago
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