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MakcuM [25]
3 years ago
11

Write the equation in slope intercept form. Then, match the equation with the correct graph.

Mathematics
1 answer:
Vitek1552 [10]3 years ago
6 0
Yes u r not correct because it’s something else
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I need help with these
3241004551 [841]

1. a= 60 (vertically opposite angles)

b= 360-(60+60)=240/2= 120 (angles at a point)

c= 120 (vertically opposite angles with b)

2. c= 90-40= 50 (vertically opposite angles)

b=a=360-90-90=180/2=90 (angles at a point)

3. a= 180-52-51= 77 (angles on a straight line)

b=52 (angles at a point)

d=51 (angles at a point)

c=77 (angles at a point)

4. a= 60 (vertically opposite angles)

b= 360-(60+60)=240/2= 120 (angles at a point)

c= 120 (vertically opposite angles with b)

e=65

d=f= 360-65-65=230/2=115

h=55

i=g=360-55-55=250/2=125

5. b=163

a=90

e=70

d=360-70-70=220/2=110

c=360-163-163=34/2=17

Hope this helps!

4 0
3 years ago
What is the vertical clearance 2 m from the edge of the tunnel?
raketka [301]
When x=0 y=50 when y=0 x=+\-5. -x^2 makes the parabola open downward y(x)=2x^2+50;y(3)=2*9+50=32
4 0
3 years ago
Asap answer pls-----------
marissa [1.9K]

Answer:

y=\frac{4}{5}x-\frac{18}{5}

Step-by-step explanation:

Hi there!

Linear equations are typically organized in slope-intercept form: y=mx+b where m is the slope and b is the y-intercept (the value of y when x is 0).

<u>1) Determine the slope (m)</u>

m=\frac{y_2-y_1}{x_2-x_1} where two points on the line are (x_1,y_1) and (x_2,y_2)

In the graph, the points (-3,-6) and (2,-2) are plotted clearly, so we can use these to help us find the slope. Plug them into the equation:

m=\frac{-6-(-2)}{-3-2}\\m=\frac{-6+2}{-3-2}\\m=\frac{-4}{-5}\\m=\frac{4}{5}

Therefore, the slope of the line is \frac{4}{5}. Plug this into y=mx+b :

y=\frac{4}{5}x+b

<u>2) Determine the y-intercept (b)</u>

y=\frac{4}{5}x+b

Typically, given a graph, we could look at where exactly the line crosses the y-axis to determine b. However, because it appears ambiguous on this graph, we must solve it algebraically.

Plug in one of the given points (2,-2) and solve for b:

-2=\frac{4}{5}(2)+b\\-2=\frac{8}{5}+b

Subtract \frac{8}{5} from both sides to isolate b

-2-\frac{8}{5}=\frac{8}{5}+b-\frac{8}{5}\\-\frac{18}{5} =b

Therefore, the y-intercept of the line is -\frac{18}{5}. Plug this back into y=\frac{4}{5}x+b:

y=\frac{4}{5}x+(-\frac{18}{5})\\y=\frac{4}{5}x-\frac{18}{5}

I hope this helps!

8 0
3 years ago
Is the volume of a triangular prism one-third the volume of a rectangular prism with the same base area and height?
Vlad [161]

Nope

Step-by-step explanation:

Volume of rectangular prism :

= Base Area × h = l × w × h

Volume of triangular prism :

= Base Area × h

Cuz the base area of triangular prism, the volume is :

(½ × l × w) × h

= ½ lwh

So, the volume of a triangular prism is half of a rectangular prism

3 0
3 years ago
.............................
garri49 [273]
12x+6 \geq 9x+12
12x-9x\geq 12-6
3x\geq 6
x\geq 6/3
x\geq 2
4 0
4 years ago
Read 2 more answers
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