Cámbiate de clase mano esa profesora esta depravada
So you maybe know that
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. Now let us try to simplify the expression
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Answer:
P=1/65.
Step-by-step explanation:
We knaow that one coin in a collection of 65 has two heads. If a coin, chosen at random from the lot and then tossed, turns up heads 6 times in a row. We calculate the probability that it is the two-headed coin.
We calculate the number of possible combinations:

Number of favorable combinations is 1.
Therefore, the probability is
P=1/65.
Answer:
basically just find the hypotenuse and show your setup/expression
a²+b²=c²
Step-by-step explanation:
bla bla bla
Hello!
2(x + 9) = 4(x + 7) + 2
Distribute the 2
2x + 18 = 4(x + 7) + 2
Distribute the 4
2x + 18 = 4x + 28 + 2
Combine like terms
2x + 18 = 4x + 30
Subtract 18 from both sides
2x = 4x + 12
Subtract 4x from both sides
-2x = 12
Divide both sides by -2
x = -6
Where she did something different than me is her mistake
Hope this helps!