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s344n2d4d5 [400]
2 years ago
15

Which one is correct a b c d

Mathematics
2 answers:
xeze [42]2 years ago
3 0

Answer:

b

Step-by-step explanation:

Goryan [66]2 years ago
3 0

its b                                                                                                sooooooooooooooooooooooooooooo

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Students who have completed a speed reading course have reading speeds that are normally distributed with a mean of 950 words pe
VikaD [51]

Answer:

36.04% probability that at most two of them would read at less than 850 words per minute

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the binomial probability distribution.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Percentage of students who read less than 850 words per minute.

Pvalue of Z when X = 850. The mean is \mu = 950 and the standard deviation is \sigma = 200

Z = \frac{X - \mu}{\sigma}

Z = \frac{850 - 950}{200}

Z = -0.5

Z = -0.5 has a pvalue of 0.3085.

30.85 of students read less than 850 words per minute.

If 10 students are selected at random, what is the probability that at most two of them would read at less than 850 words per minute

This is P(X \leq 2) when n = 10, p = 0.3085. So

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.3085)^{0}.(0.6915)^{10} = 0.0250

P(X = 1) = C_{10,1}.(0.3085)^{1}.(0.6915)^{9} = 0.1115

P(X = 2) = C_{10,2}.(0.3085)^{2}.(0.6915)^{8} = 0.2239

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0250 + 0.1115 + 0.2239 = 0.3604

36.04% probability that at most two of them would read at less than 850 words per minute

8 0
3 years ago
What is the solution of log2x + 6 8 = 3? (6 points)
photoshop1234 [79]

Step-by-step explanation:

log(2x)   + 68 = 3 \\  log(2)  +  log(x)  + 68 = 3 \\  log(x)  =  - 65.30103 \\ x =  {10}^{ - 65.30103}  = \\ x =  5 \times  {10}^{ - 66}

4 0
3 years ago
A recipe for coffe cake calls for 8 cups of instant coffe. Convert this to milliliters
lyudmila [28]

Answer:

you need to use volume conversions for example like the metric system i had to use not to long ago use the common cooking conversion (its a conversion)

Step-by-step explanation:


6 0
3 years ago
Simplify 3V5x•3V25x2
Usimov [2.4K]

Answer:

Step-by-step explanation:

7 0
3 years ago
The diameter of small Nerf balls manufactured overseas is expected to be approximately normally distributed with a mean of 5.2 i
ioda

Answer:

5.2 inches

Step-by-step explanation:

The diameter of small Nerf balls follows normally distribution with mean 5.2 inches and standard deviation 0.08 inches.

We have to calculate the mean of sampling distribution when 20 balls are selected randomly.

Here, μ=5.2 and σ=0.08.

We know that mean of sampling distribution for mean is equal to the population mean.

mean of sampling distribution for mean= μxbar=μ= 5.2

Thus, mean of the sampling distribution of the sample mean is 5.2 inches

7 0
3 years ago
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