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Gnom [1K]
2 years ago
13

Market researchers were interested in the relationship between the number of pieces in a building-brick set and the cost of the

set. The researchers collected information from a survey and used it to obtain the regression equation y = 0.08x + 1.20, where x represents the number of pieces in a set and y is the predicted price (in dollars) of the set. What is the predicted price of a set that has 2,520 pieces?
A. $202.80
B. $2,017.20
C. $3,024.08
D. $31,485
Mathematics
1 answer:
sertanlavr [38]2 years ago
6 0

The answer would be D.

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A taxi charges a pick-up fee p!us a charge per mile. Maria paid $15.00 for a 7 mile rode. To my paid $19.50 for a 10 mile ride.
lukranit [14]

Answer:

The y-intercept in coordinate form is (0, 4.5) and represents the taxi pick-up fee.  The equation is y=1.5x + 4.5.

Step-by-step explanation:

This question is asking for the slope and y-intercept of a linear equation.  A linear equation makes a straight line based on a constant rate of change.  For this problem, the cost per mile is the slope, while the independent variable 'x' is the number of miles and the dependent variable 'y' is the total cost.  In order to first find slope, you need to use the two points given (7, 15) and (10, 19.5) to set up a change in y / change in x, or (19.5-15)/(10-7) or 4.5/3 which is 1.5.  So the slope, or cost per mile is $1.50.  To find the y-intercept (b), or the cost of the pick-up fee, simply fill in your equation y=1.5x + b with your other variables and solve for 'b'.  So, 15 = (1.5 x7) + b.  or 15 = 10.5 +b, subtract 10.5 from both sides of the equation to get b=4.5.  

5 0
4 years ago
Mrs. Magdalino kept records on how much she spent on gasoline and the maintenance of her car. She found that it cost $485 to dri
algol [13]

Answer:

  • C = 0.97m
  • $1164 for 1200 miles
  • 845 miles for $820

Step-by-step explanation:

Given a car's cost of operation is $485 for 500 miles, you want an equation relating cost for m miles, and solutions to that equation for 1200 miles, and for a cost of $820.

<h3>Cost per mile</h3>

The cost per mile is found by dividing the cost by the associated number of miles:

  $485/(500 mi) = $0.97 /mi

<h3>Equation</h3>

The equation for the cost will show the cost as the cost per mile multiplied by the number of miles:

  C = 0.97m . . . . . where C is cost in dollars for m miles driven

<h3>1200 miles</h3>

The cost for driving $1200 miles will be ...

  C = 0.97(1200) = $1164

The cost of driving 1200 miles is $1164.

<h3>$820</h3>

The number of miles that can be driven for a cost of $820 is ...

  820 = 0.97m

  m = 820/0.97 = 845.36

About 845 miles are driven for a cost of $820.

3 0
1 year ago
What number line represents the solution to n + 2 &lt; 8
Delicious77 [7]

Answer:

its y

Step-by-step explanation:

5 0
3 years ago
A shipment of 18 televisions sets contains 3 defective sets. A hotel purchases 8 of these televisions sets. What is the probabil
Allisa [31]

Answer:

85.29%

Step-by-step explanation:

We know 18 televisions sets contains 3 defective sets => 15 TV sets are ok

So the total number of possible ways for the hotel to buy = C^{18} _{8} = 43758

At least one of the defective sets, so we need to find the probability for 1 defective sets, 2 defective sets and 3 defective sets.

1. The number of ways  the hotel purchases 8 of these televisions sets but have 1 defective one:

P(1) = C^{15} _{7} * C^{3} _{1} = 6435*3 = 19305

2.  The number of ways  the hotel purchases 8 of these televisions sets but have 2 defective one:

P(2) = C^{15} _{6} * C^{3} _{2} = 5005*3= 15015

3.  The number of ways  the hotel purchases 8 of these televisions sets but have 3 defective one:

P(3) = C^{15} _{5} * C^{3} _{3} = 3003*1 = 3003

So the probability that the hotel receives at least one of the defective sets =

(P(1) + P(2) + P(3) ) / P = (19305 +15015 + 3003 ) / 43785*100% = 85.29%

6 0
3 years ago
1. Evaluate the discriminant for each equation, then use it to determine the nature of the roots for each quadratic equation.
Marizza181 [45]

Given the quadratic equation ax^2 + bx + c = 0, the coefficients of x^2, x and 1 are a, b and c respectively.  

(a) and (b) are not valid quadratics, because they omit the exponent 2.   Rewrite these as comments within your original post, please.

(c) 4x^2+20x+25=0:  Here, a = 4, b = 20 and c = 25.

6 0
3 years ago
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