To calculate the area between both curves, we must calculate the following integrals:
int a-b [f (x)] dx
int a-b: integral from a to b
f (x): function
Enter [0, (π / 2)]
int 0-π / 2 [(7 cos (x) -7sin (x))] dx = int 0 -π / 2 [(7 cos (x)] dx + int 0-π / 2 [-7sin (x) )] dx
Calculated:
int 0-π / 2 [(7 cos (x)] dx = 7 (sin (π / 2) - sin (0)) = 7 (1-0) = 7
int 0-π / 2 [-7 sin (x))] dx = 7 (cos (π / 2) - cos (0)) = 7 (0-1) = - 7
int 0-π / 2 [(7 cos (x) -7sin (x))] dx = 7 + (-7) = 0
answer
the area of the region bounded by the x-axis and the curves y = 7sin (x) and y = 7 cos (x) where x∈ [0, (π / 2)] is
A=0
W=340-z (vice versa)
x=540-w (vice versa)
y=-150+x (vice versa)
z=-50+y ( vice versa)
B. Associative Property Of Multipication
<u>Answer</u>:
Therefore has one solution.
<u>explanation</u>:
Given equations:
6x + y = -7
-24x -7y = 25
Make y the subject:
6x + y = -7
y = -7 - 6x ..............equation 1
-24x -7y = 25
-7y = 25 + 24x
y = (25 + 24x)/-7 ..........equation 2
Solve them simultaneously:
(25 + 24x)/-7 = -7 - 6x
25 + 24x = -7 (-7 - 6x)
25 + 24x = 49 + 42x
42x - 24x = 25- 42
18x = -24
x = 
Then y is:
y = -7 - 6x
y = -7 - 6( )
y = 1
Has one separate value of x and y: ( , 1 ); so it has one solution.
Answer:
Step-by-step explanation:
y=mx+C
M= slope
2= -2(1)+ C
2 = -2+C
C = 2+2
C = 4
<h3>Equation: y = -2x + 4</h3>
