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soldier1979 [14.2K]
4 years ago
14

Read the top and answer 100 points

Mathematics
2 answers:
77julia77 [94]4 years ago
7 0

Answer:

1)30.1029995664

2)69.2980392812

3)168.080670083

4)(3x/3=13/3

x=4.33333333333

5)5x-(5000)=0

5x=5000

x=5000/5

x=1000

6)(2)3(x+2)=(6000)=0

23x+46-6000=0

23x-5954=0

23x=5954

x=5954/23

x=258+20/23

Hope this help you!

Keith_Richards [23]4 years ago
7 0

Answer

Step-by-step explanation:

1)30.1029995664

2)69.2980392812

3)168.080670083

4)(3x/3=13/3

5)5x-(5000)=0

5x=5000

6)(2)3(x+2)=(6000)=0

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pashok25 [27]
To answer this, set up a system of equations. What we know is that

5x + 2y = 100
And...
x+y=38

x represents the unknown number of 5 points questions
y represents the unknown number of 2 point questions

In my opinion the easiest way to solve this is to use substitution (that is when you find out the value of one variable, either x or y, and substitute that value as the variable).

So,

x+y=38

Subtract x from both sides

y=38-x

Now, plug (38-x) in as y in the other equation.

5x + 2(38-x) = 100
5x + 76-2x= 100
3x+76=100
3x=24
x=8

Now that you know that x=8, you can solve for y.

5x+2y=100
5(8)+2y=100
40+2y=100
2y=60
---- ------
2 2
y=30


X=8
Y=30

There are 8 five point questions on the test and 30 two point questions on the test

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3 years ago
Find the coordinate of E'
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Find the demand function for the marginal revenue function. Recall that if no items are​ sold, the revenue is 0.
Pepsi [2]

The integral that is needed to solve the demand function is R(x) = 599x - 0.14x^{3/2}

<h3>What is Demand Function?</h3>

A demand function describes the mathematical relationship between the quantity demanded and one or more determinants of the demand, as the price of the good or service, the price of complementary and substitute goods, disposable income, etc.

Here, given differential equation;

R'(x) = 599 - 0.21\sqrt{x}

we can also write this as;

\frac{d}{dx}R(x) = 599 - 0.21\sqrt{x}

d R(x) = (599 - 0.21\sqrt{x} ) dx

On integrating both sides, we get

\int\ d R(x) = \int\ (599 - 0.21\sqrt{x} ) dx

R(x) = 599x - 0.21 X \frac{2}{3}x^{3/2} + C

R(x) = 599x - 0.14x^{3/2} + C       ...........(i)

Also given, at x = 0, R(x) = 0, Put these values in equation (i), we get

0 = 0 - 0 + C

C = 0

Put the value of C in equation (i), we get

R(x) = 599x - 0.14x^{3/2}

Thus, the integral that is needed to solve the demand function is R(x) = 599x - 0.14x^{3/2}

Learn more about Demand Function from:

brainly.com/question/20564722

#SPJ1

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