All categories

3 years ago

Simplify (−6.5)(2)( −5). 65 6.5 −6.5 −65 pls I give points

Mathematics

2 answers:

algol [13]3 years ago

6 0

Answer:

Step-by-step explanation:

→ First multiply the whole numbers together

2 × -5 = -10

→ Now multiply -10 by -6.5

-6.5 × -10 = 65

Naddik [55]3 years ago

3 0

was replaced by "(65/10)

1. 65/10 = 13

—

Equation at the end of step:

((0 - ——) × 2) × -5

Answer = 65

You might be interested in

Anybody can do it I believe in y'all pls

yKpoI14uk [10]

13 miles per hour

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

24x^6y^2

belka [17]

Answer:

Step-by-step explanation:

8 0

3 years ago

Two bicyclists ride in opposite directions. The speed of the first bicyclist is 5mph faster than the second. After 2 hours they

kirza4 [7]

Answer:

A. 15 mi/h; 20 mi/hr

Step-by-step explanation:

3 0

1 year ago

Solve for x, show work please! 20 points!

GuDViN [60]

<h2>Option A </h2>

Step-by-step explanation:

Here,

70° = 12x - 2 [Since Vertically Opposite Angles]

=> 12x - 2 = 70

=> 12x = 72

$= > x = \frac{72}{12}$

=> x = 6 (Ans) (Option A)

8 0

3 years ago

The savings account offering which of these APRs and compounding periods offers the best APY?

ANTONII [103]

A)

$\bf \qquad \qquad \textit{Annual Yield Formula}
\\\\
\left. \qquad \qquad\right. \left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 3.1196\%\to \frac{3.1196}{100}\to &0.031196\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annually, thus twice}
\end{array}\to &2
\end{cases}
\\\\\\
\left. \qquad \qquad\right. \left(1+\frac{0.031196}{2}\right)^{2}-1$

b)

$\bf \qquad \qquad \textit{Annual Yield Formula}
\\\\
\left. \qquad \qquad\right. \left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 3.1184\%\to \frac{3.1184}{100}\to &0.031184\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, thus four times}
\end{array}\to &4
\end{cases}
\\\\\\
\left. \qquad \qquad\right. \left(1+\frac{0.031184}{4}\right)^{4}-1$

c)

$\bf \qquad \qquad \textit{Annual Yield Formula}
\\\\
\left. \qquad \qquad\right. \left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 3.1095\%\to \frac{3.1095}{100}\to &0.031095\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{daily, assuming 365 days}
\end{array}\to &365
\end{cases}
\\\\\\
\left. \qquad \qquad\right. \left(1+\frac{0.031095}{365}\right)^{365}-1$

d)

$\bf \qquad \qquad \textit{Annual Yield Formula}
\\\\
\left. \qquad \qquad\right. \left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 3.1172\%\to \frac{3.1172}{100}\to &0.031172\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{monthly, thus twelve times}
\end{array}\to &12
\end{cases}
\\\\\\
\left. \qquad \qquad\right. \left(1+\frac{0.031172}{12}\right)^{12}-1$

8 0

4 years ago

Read 2 more answers