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Svetradugi [14.3K]

3 years ago

11

?????????????????????!

2 answers:

xxTIMURxx [149]3 years ago

7 0

Answer:

Net Force: 3N Direction: Right

Step-by-step explanation:

The forces pushing the box (cube? square?) from the top and the bottom cancel out, since they are both 4N. Then, if you subtract the 4N pushing from the right from the 7N pushing from the left, you get 3N. SInce it is pushing from the left, the object would move to the right,

Digiron [165]3 years ago

6 0

Answer:

net force 3 direction right/east

Step-by-step explanation:

....

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Describe the sequence of translations used to move figure 1 onto figure 2

Elanso [62]

Answer:

dilation 10 left and 3 down

Step-by-step explanation:

8 0

3 years ago

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3 years ago

To solve this system of equations by elimination, what operation could be used to eliminate the x-variable and find the value of

babymother [125]

Answer:

The value of y is $y=\frac{42}{17}$

Step-by-step explanation:

we have

$4x+3y=6$ -----> equation A

$18x+5y=6$ -----> equation B

To eliminate the x-variable and find the value of y Multiply the equation A by -18/4 both sides or multiply the equation B by -4/18 both sides

I choice

Multiply the equation A by -18/4 both sides

$(-18/4)[4x+3y]=6*(-18/4)$

$-18x-13.5y=-27$ ------> equation C

Adds equation B and equation C

$18x+5y=6\\-18x-13.5y=-27\\-------\\5y-13.5y=6-27\\-8.5y=-21\\\\ y=\frac{42}{17}$

7 0

3 years ago

A 30° 60° 90° triangle is shown below. Find the length of the side labeled y.

bulgar [2K]

Answer:

Part 1) $y=3\ units$

Part 2) The length of the hypotenuse is 6 units

Step-by-step explanation:

Part 1) we know that

In the right triangle of the figure

$sin(60^o)=\frac{y}{2\sqrt{3}}$ ----> by SOH (opposite side divided by the hypotenuse)

solve for y

$y=sin(60^o)2\sqrt{3}$

Remember that

$sin(60^o)=\frac{\sqrt{3}}{2}$

substitute

$y=(\frac{\sqrt{3}}{2})2\sqrt{3}$

$y=3\ units$

Part 2)

Let

h ----> the length of the hypotenuse

we know that

In the right triangle of the figure

$sin(45^o)=\frac{3\sqrt{2}}{h}$ ----> by SOH (opposite side divided by the hypotenuse)

$h=\frac{3\sqrt{2}}{sin(45^o)}$

Remember that

$sin(45^o)=\frac{\sqrt{2}}{2}$

substitute

$h=3\sqrt{2}:\frac{\sqrt{2}}{2}$

$h=6\ units$

7 0

3 years ago

Plz help me with this math question

jok3333 [9.3K]

Answer:

79

Step-by-step explanation:

Order of operations GERMDAS

Grouping: no grouping

Exponents: 9²=81 so 6÷3+81-4

Radicals: no radicals

Multiplication: no multiplication

Division: 6÷3=2 so 2+81-4

Addition: 2+81=83 so 83-4

Subtraction: 83-4=79

4 0

3 years ago

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