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beks73 [17]
3 years ago
11

PLEASE HELP DUE SOON PLEASE !!

Mathematics
1 answer:
sukhopar [10]3 years ago
4 0

Answer:

(1 + \sqrt{3} ) : 3

Step-by-step explanation:

AB = x\sqrt{3}  cm

BC = x cm

Area = l * b = x\sqrt{3} * x

= x^2 \sqrt{3}

EFG is equilateral triangle

EF = y cm

Area of triangle = (\sqrt{3} / 4) * a^{2}

A = (\sqrt{3} / 4) * y^{2}

As both areas are equal

\sqrt{3} x^{2}  = \sqrt{3} /4 * y^{2}

4x^{2}  = y^{2}

2x = y

perimeter of ABCD = 2 (l + b)

2 (x\sqrt{3}  + x)\\= 2x(\sqrt{3} + 1)

perimeter of EFG = 3y

so ratio is 2x(\sqrt{3} + 1) : 3y

substitute y = 2x

2x(\sqrt{3} + 1) : 3*2x\\(\sqrt{3}  + 1) : 3

(1 + \sqrt{3} ) : 3

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