Find the 71st term. 8, 14, 20, 26, ...

The volume of a large aquarium is 210 yd. It is 3 yd wide and 2

Pavel [41]

Length of the aquarium is 35 yd

Step-by-step explanation:

Step 1: Volume of the aquarium = 210 yd³ given by Volume = length × width × height. Width = 3 yd and Height = 2 yd

Length = Volume/Width × Height

= 210/3 × 2 = 210/6

= 35 yd

5 0

3 years ago

Mehvish buys 1/2 kg carrots, 3 kg potatoes, 2 kg onions and 1 1/2kg of chicken.

ozzi

Answer:

The amount of change will be £7.99

Step-by-step explanation:

Here, we want to calculate the amount of change that Mehvish should get

1/2 kg carrots at 50 p per kg will be;

1/2 * 50 = 25 p

3 kg potatoes at 64 p per kg will be

3 * 64 = p 192

2 kg onions at 42 p per kg

2 * 42 p = 84 p

1 1/2 kg chicken at £6 per kg will be:

since £1 is 100 p

1.5 * 6 = £9 (9 * 100 p = 900p)

since £1 is 100 p

£20 will be;

20 * 100 = 2,000 p

So let us make the subtraction as follows;

2,000- 900 - 84-192 - 25 = 799 p

In pounds, this is divided by 100

we have this as 799/100 = £7.99

7 0

3 years ago

If you flip a fair coin 7 times, what is the probability that you will get exactly 4 tails?

andre [41]

Probability that you will get exactly 4 tails, if you flip a fair coin 7 times is: $\frac{35}{128}$

Step-by-step explanation:

We need to find the probability that you will get exactly 4 tails, if you flip a fair coin 7 times.

This is the combination question.

The total combinations will be: 2^7=128

Now, finding number of ways we can get exactly 4 tiles:

We will use the formula:

$^nC_k=\frac{n!}{k!(n-k)!}$

in our given question, n= 7, k= 4

Putting values:

$^nC_k=\frac{n!}{k!(n-k)!}\\^7C_4=\frac{7!}{4!*3!}\\ ^7C_4=\frac{7*6*5*4!}{4!*3!}\\ ^7C_4=\frac{7*6*5}{6}\\ ^7C_4=35$

So, Probability that you will get exactly 4 tails, if you flip a fair coin 7 times is: $\frac{35}{128}$

Keywords: Probability

Learn more about Probability at:

#learnwithBrainly

7 0

3 years ago

A communications channel transmits the digits 0 and 1. However, due to static, the digit transmitted is incorrectly received wit

m_a_m_a [10]

Answer:

The probability that the message will be wrong when decoded is 0.05792

Step-by-step explanation:

Consider the provided information.

To reduce the chance or error, we transmit 00000 instead of 0 and 11111 instead of 1.

We have 5 bits, message will be corrupt if at least 3 bits are incorrect for the same block.

The digit transmitted is incorrectly received with probability p = 0.2

The probability of receiving a digit correctly is q = 1 - 0.2 = 0.8

We want the probability that the message will be wrong when decoded.

This can be written as:

$P(X\geq3) =P(X=3)+P(X=4)+P(X=5)\\P(X\geq3) =\frac{5!}{3!2!}(0.2)^3(0.8)^{2}+\frac{5!}{4!1!}(0.2)^4(0.8)^{1}+\frac{5!}{5!}(0.2)^5(0.8)^0\\P(X\geq3) =0.05792$

Hence, the probability that the message will be wrong when decoded is 0.05792

4 0

3 years ago

Please help me ASAP will mark brianlest

Paul [167]

Answer:

idk a or c

Step-by-step explanation:

5 0

3 years ago