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If the standard deviation of an exam is 5, the z-score us 1.95 and the mean is 80, the actual test score is; 89.75
<h3>How to solve z-score problems?</h3>
We are given;
Standard deviation; s = 5
z-score = 1.95
Mean = 80
Formula for z-score is;
z = (x' - μ)/σ
Thus;
1.95 = (x' - 80)/5
1.95 * 5 = (x' - 80)
9.75 = x' - 80
x' = 80 + 9.75
x' = 89.75
Read more about Z-score Problems at; brainly.com/question/25638875
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10y - 5x = 40 Add 5x to both sides
10y = 5x + 40 Divide both sides by 10
y =

x + 4
The
y-intercept is 4 and the
slope of the line is 
.
You can find these by comparing your equation to the equation y = mx + b, where m is the slope of the line and b is the y-intercept.
Answer:
Interval [16.34 , 21.43]
Step-by-step explanation:
First step. <u>Calculate the mean</u>

Second step. <u>Calculate the standard deviation</u>



As the number of data is less than 30, we must use the t-table to find the interval of confidence.
We have 6 observations, our level of confidence DF is then 6-1=5 and we want our area A to be 80% (0.08).
We must then choose t = 1.476 (see attachment)
Now, we use the formula that gives us the end points of the required interval

where n is the number of observations.
The extremes of the interval are then, rounded to the nearest hundreth, 16.34 and 21.43