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arlik [135]
3 years ago
12

two comets orbit the Sun. One comet travels 30,000 miles per hour and the other comet travels 28,500 miles per hour. What is the

most efficient way to calculate the difference of the distances traveled by the comets for any given number of minutes? Justify your answer.
Mathematics
1 answer:
GenaCL600 [577]3 years ago
7 0

The difference of the distances traveled by the comets for any given number of minutes is 25t.

Since the first comet travels at a speed of 30,000 miles per hour, the distance it travels in t minutes is d = 30000 mph × 1 h/60 min × t = 500t miles.

Also, the second comet travels at a speed of 28,500 miles per hour, the distance it travels in t minutes is d' = 28,500 mph × 1 h/60 min × t = 475t miles.

So, the difference in the distances traveled by the comets D = d - d'

= 500t - 475t

= 25t

So, the difference of the distances traveled by the comets for any given number of minutes is 25t.

Learn more about distance traveled by comets here:

brainly.com/question/11458136

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Use the distributive property to find an expression that is equivalent to 27x2(second power)-42x+12
Lina20 [59]
27x^2 - 42x + 12

3 is a common factor:-

= 3(9x^2 - 14x + 4)

That is the equivalent expression.
5 0
3 years ago
The cost for 15 cases of oranges is $75. What is the cost for 1 case? *
postnew [5]

Answer:Ok I This question can be solved using a system of equation, which requires translating the above word problem into something that can be algebraically

Let O=oranges and  Let G=Grapefruit

5O +8G=235

3O + 2G=85

To solve, you must isolate one of the variables and then work from there. To do that multiply both sides of the bottom or second equation by four and then subtract the bottom equation from the top.

Which would look like this

5O +8G=235

12O + 8G= 340

Then subtract the bottom from the top to get this

-7O=-105

Solving for O we divide both sides by -7, and end up with O=15

Plugging that value back into one of our original equations to solve for G we get this

3(15) + 2G= 85

45 +2G=85

2G=40

G=20

So 1 case of each altogether would equal 15+20, or $35.

<h3>Hope this helps have a awesome night/day❤️✨</h3>

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
For what value of x is the equation 2^2x+7 = 2^15 true?
GenaCL600 [577]

Answer:

  x = 4

Step-by-step explanation:

We assume your equation is intended to be ...

  2^(2x+7) = 2^15

Equating exponents gives ...

  2x +7 = 15

  2x = 8 . . . . . . subtract 7

  x = 4 . . . . . . . divide by 2

The value of x is 4.

8 0
4 years ago
PLEASE HELP I HAVE AN HOUR LEFT!!
Yuki888 [10]

The statement that correctly describes the horizontal asymptote of g(x) is:

Limit of g (x) as x approaches plus-or-minus infinity = 6, so g(x) has an asymptote at y = 6.

<h3>What are the asymptotes of a function f(x)?</h3>

  • The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.
  • The horizontal asymptote is the limit of f(x) as x goes to infinity, as long as this value is different of infinity.

In this problem, the function is:

g(x) = \frac{42x^3 - 15}{7x^3 - 4x^2 - 3}

The horizontal asymptote is given as follows:

y = \lim_{x \rightarrow \infty} g(x) = \lim_{x \rightarrow \infty} \frac{42x^3 - 15}{7x^3 - 4x^2 - 3} = \lim_{x \rightarrow \infty} \frac{42x^3}{7x^3} = \lim_{x \rightarrow \infty} 6 = 6

Hence the correct statement is:

Limit of g (x) as x approaches plus-or-minus infinity = 6, so g(x) has an asymptote at y = 6.

More can be learned about asymptotes at brainly.com/question/16948935

#SPJ1

5 0
2 years ago
You toss 3 fair coins in the air at once.
MAVERICK [17]
The probability of a head or tail upon flipping is 50-50. THe asnwers are as followsL
a. {HHH, HHT, HTT, TTT, TTH, THH, HTH, THT}b and c.  p = 3C3 * 0.5^3 = 0.125d. from a, p = 3/8 = 0.375e. from a, p = 3/8 = 0.375f. 0.875
5 0
4 years ago
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