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Advocard [28]
3 years ago
10

What is the set of days with names containing the letter r

Mathematics
1 answer:
Nikolay [14]3 years ago
7 0

Answer:there is only 2 days that contain the letter r

Step-by-step explanation:

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Montano1993 [528]

Answer:

subscribe to Sky Clikz on YT  to make you and my day better

Step-by-step explanation:

5 0
4 years ago
Read 2 more answers
A Geiger counter counts the number of alpha particles from radioactive material. Over a long period of time, an average of 14 pa
UkoKoshka [18]

Answer:

0.2081 = 20.81% probability that at least one particle arrives in a particular one second period.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Over a long period of time, an average of 14 particles per minute occurs. Assume the arrival of particles at the counter follows a Poisson distribution. Find the probability that at least one particle arrives in a particular one second period.

Each minute has 60 seconds, so \mu = \frac{14}{60} = 0.2333

Either no particle arrives, or at least one does. The sum of the probabilities of these events is decimal 1. So

P(X = 0) + P(X \geq 1) = 1

We want P(X \geq 1). So

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-0.2333}*(0.2333)^{0}}{(0)!} = 0.7919

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.7919 = 0.2081

0.2081 = 20.81% probability that at least one particle arrives in a particular one second period.

8 0
4 years ago
Find the area of the shape shown below
myrzilka [38]

Answer: 42.5

Step-by-step explanation:

9 x 3.5 = 31.5

2 x 2 = 4

2 x 2 / 2 = 2

2 x 5 / 2 = 5

31.5 + 4 + 2 + 5 = 42.5

6 0
3 years ago
PLEASE HELP SOLVE. i believe the answer is 50cm^2. can someone help.
hichkok12 [17]

Answer:

3 cm

Step-by-step explanation:

So the area of the total circle is:

\pi \times 5^{2}  = \pi \times 25

If you remove the outer band you have the area of the inner circle

25\pi - 16\pi = 9\pi

This means that the inner circle had an area of

area = pi * r^2

9 pi = pi * r^2

r =

\sqrt{9}  = 3

So the radius of the inner circle is 3.

4 0
3 years ago
Answer this for brainiest:)
Norma-Jean [14]

Answer:

Your in my class

Step-by-step explanation:

L M A O let me know when you get the answer

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3 years ago
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