Answer:
A sample size of 183 is needed.
Step-by-step explanation:
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of 
.
That is z with a pvalue of 
, so Z = 2.17.
Now, find the margin of error M as such
In which 
is the standard deviation of the population and n is the size of the sample.
Margin of error within 0.023 ppm of mercury with 97% confidence. What sample size is needed?
We have to find n for which 
. We have that 
. So
We have to round up(182 is not quite in the desired margin of error), so a sample size of 183 is needed.
’32.725 is less than. 32.735
Answer:
the number of sheet available is 75, 000
you take the total number of pages available = 8 x 75,000
= 600,000 pages
then each notebooks contains 200 pages
= 600,000 / 200
= 3000 notebooks can be made
Step-by-step explanation:
Answer:
b
Step-by-step explanation:
