Andre says that 3 \div÷ 2/3 = because there are 4 groups of 2/3 and 1/3 left. Do you agree with Andre?

Mathematics

1 answer:

xenn [34]3 years ago

3 0

Answer: No

Is this 3/(2/3)? I'll assume it is.

Step-by-step explanation:

3/(2/3) can be rewritten as 3*(3/2)

3*(3/2) = 9/2 or 4 1/2

Four groups of 2/3 would make 8/3 or 2 2/3, not 4 and 1/3.

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Step-by-step explanation:

Step 1

The fist step is to define the probabilities.

The events are independent from each other. Each team wins with probability $\frac{1}{2}$ and looses with probability $\frac{1}{2}.$ Let $P(W_R)$ be probability that Roses win and $P(L_R)$ be the probability that Roses loose.

Step 2

The second step is to calculate the probabilities by multiplying the probabilities with the first 3 terms in the product being the probability of a win and the last term being the probability of a loss.

The calculation is shown below,

$P(W_R)\times P(W_R)\times P(W_R)\times P(L_R)=\frac{1}{2} \times \frac{1}{2} \times\frac{1}{2} \times\frac{1}{2} =\frac{1}{16}$