Please help 10 points 1 question

Find three consecutive even integers whose sum is −24

labwork [276]

Answer: $-10,-8,-6$

Step-by-step explanation:

Let be:

$x$ , $x+2$ and $x+4$ the three consecutive even integers whose sum is -24

Then, we can write this expression:

$x+(x+2)+(x+4)=-24$

Now, we must solve for "x":

$3x+6=-24\\\\3x=-24-6\\\\3x=-30\\\\x=\frac{-30}{3}\\\\x=-10$

Then you get that the others integers are:

$x+2=-10+2=-8$

$x+4=-10+4=-6$

Therefore, the three consecutive even integers whose sum is -24 are:

$-10,-8,-6$

6 0

3 years ago

Read 2 more answers

Help me with this problem

DedPeter [7]

Answer:

B i did the test

Step-by-step explanation:

Hope this helps! (:

8 0

2 years ago

Help me guys fast as

Viktor [21]

cos(180-x)=-cosX

$\\ \rm\Rrightarrow tan^2135-cosec^260=-xcos45.sin45.cot60$

$\\ \rm\Rrightarrow (-1)^2-(\dfrac{2}{\sqrt{3}})^2=-\dfrac{x}{\sqrt{2}}\times \dfrac{1}{\sqrt{2}}\times \dfrac{1}{\sqrt{3}}$

$\\ \rm\Rrightarrow 1-\dfrac{4}{3}=\dfrac{-x}{2\sqrt{3}}$

$\\ \rm\Rrightarrow \dfrac{3-4}{3}=\dfrac{-x}{2\sqrt{3}}$

$\\ \rm\Rrightarrow \dfrac{-1}{3}=\dfrac{-x}{2\sqrt{3}}$

$\\ \rm\Rrightarrow \dfrac{1}{\sqrt{3}}=\dfrac{x}{2}$

$\\ \rm\Rrightarrow x=\dfrac{2}{\sqrt{3}}$

4 0

2 years ago

An airplane leaves an airport at 9:00 p.M. With a heading of 270 and a speed of 610 mph. At 10:00 p.M. The pilot changes the he

timama [110]

Answer:

2330.51 miles

Step-by-step explanation:

Given that the speed of the airplane = 610 mph.

The airplane leaves an airport at 9:00 P.M. with a heading of 270 degrees and at 10:00 P.M., the pilot changes the heading to 310 degrees.

So, for 1 hour the plane is heading at 270 degrees and for 3 hours, from 10:00 p.m to 1:00 a.m, the plane is heading at 310 degrees as shown in the figure.

As, distance = time x speed, so

The distance covered at 270 degrees, $d_1 = 1\times610=610$ miles.

The distance covered at 310 degrees, $d_2 = 3\times610=1830$ miles.

Total distance covered, d, is the magnitude of the sum of vectors $\vec{d_1}$ and $\vec{d_2}$ as shown in the figure.

The angle between the vectors $\vec{d_1}$ and $\vec{d_2}$ , $\theta=310-270=40$ degree.

Magnitude of sum of the vectors \vec{d_1} and \vec{d_2},

$d= \sqrt{|\vec{d_1}|^2+|\vec{d_2}|^2+2|\vec{d_1}|\;|\vec{d_2}|\cos\theta} \\\\\Rightarrow d=\sqrt{610^2+1830^2+2|\vec{d_1}|\;|\vec{d_2}|\cos\(40^{\circ})}$

$\Rightarrow d=2330.51$ miles

Hence, at 1:00 a.m, the airplane is at a distance of 2330.51 miles from the airport.

4 0

3 years ago

Please help!!!!!!! im so confused lol

pav-90 [236]

Answer:

a : c = 7 : 10

Step-by-step explanation:

The two ratios (a : b and b : c) both have b in common, so to work out what a : c is, we can use b to 'bridge' the two ratios together.

However, in a : b, b is 4. But in b : c, b is 2. We need to make sure b is the same in both ratios before we can combine the ratios together. The easiest way to do this is to multiply b : c by 2 to get b : c = 4 : 10. Now b is 4 in both ratios.

So now, we can combine the two ratios together to get a : b : c = 7 : 4 : 10. Since we only want a : c though, we can just drop the b and get a : c = 7 : 10. No simplifying is necessary since the ratio is already in its simplest form.

Hope that helps! :)

5 0

2 years ago