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3 years ago

Please help 10 points 1 question

Mathematics

1 answer:

gregori [183]3 years ago

4 0

Answer:

ty for point have a nice day po

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Line___is a transversal.

iVinArrow [24]

Answer:

Step-by-step explanation:

Line A is Parallel to Line B

Line C intersects Line A and B

4 0

3 years ago

Read 2 more answers

In the diagram, what is mZVSR?

sesenic [268]

Answer:

80 degrees.

180-100=80

hope that helps

Please said thanks

5 0

3 years ago

I need help on these 2 questions. Algebra 1

hammer [34]

Answer:

7. is G

8. f(4)=-120

Step-by-step explanation:

7. les do f(0)=4 since its the easiest

F. f(0)=0.4(0+5)(0-2)

0.4*-2*5=-4 NOT IT. the ans. is +

G. f(0)=-0.4(0+5)(0-2)

-0.4*-2*5=4 YESSSSSS

H. f(0)=-0.4(0-5)(0+2)

-0.4*2*-5=4 YESSSSSS

J. f(0)=0.4(0-5)(0+2)

0.4*2*-5=-4 NOT ITTTT

so G n H

Put both equation=0

G. 0=-0.4(x+5)(x-2)

x=-5,2 YASSSS this is the ans.

4 0

3 years ago

Find the fractional notation for the ratio 5 to 9

vazorg [7]

5:9 is just 5/9
Hope this helps!

5 0

3 years ago

You find an interest rate of 10% compounded quarterly. Calculate how much more money you would have in your pocket if you had us

Elena-2011 [213]

Answer:

see the explanation

Step-by-step explanation:

we know that

step 1

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$r=10\%=10/100=0.10\\n=4$

substitute in the formula above

$A=P(1+\frac{0.10}{4})^{4t}$

$A=P(1.025)^{4t}$

Applying property of exponents

$A=P[(1.025)^{4}]^{t}$

$A=P(1.1038)^{t}$

step 2

The formula to calculate continuously compounded interest is equal to

$A=P(e)^{rt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

e is the mathematical constant number

we have

$r=10\%=10/100=0.10$

substitute in the formula above

$A=P(e)^{0.10t}$

Applying property of exponents

$A=P[(e)^{0.10}]^{t}$

$A=P(1.1052)^{t}$

step 3

Compare the final amount

$P(1.1052)^{t} > P(1.1038)^{t}$

therefore

Find the difference

$P(1.1052)^{t} - P(1.1038)^{t}$ ----> Additional amount of money you would have in your pocket if you had used a continuously compounded account with the same interest rate and the same principal.

3 0

3 years ago