Find the 13th term of the geometric sequence 4, -8, 16
1 answer:
Answer:
a=4
r = \frac{-16}{4}r=4−16
r = -4r=−4
a_{13} = 4×(-4)^{(13-1)}a13=4×(−4)(13−1)
a_{13} = 4×(-4)^{12}a13=4×(−4)12
a_{13} = 4×16777216a13=4×16777216
a_{13} = 67108864a13=67108864
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