Question

Find the 13th term of the geometric sequence 4, -8, 16​

Answer 1

Answer:

a=4

r = \frac{-16}{4}r=4−16

r = -4r=−4

a_{13} = 4×(-4)^{(13-1)}a13=4×(−4)(13−1)

a_{13} = 4×(-4)^{12}a13=4×(−4)12

a_{13} = 4×16777216a13=4×16777216

a_{13} = 67108864a13=67108864