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topjm [15]
3 years ago
7

Solve the math problem

Mathematics
1 answer:
vfiekz [6]3 years ago
5 0

Answer:

Oof

Step-by-step explanation:

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1 minus 2 over x minus 3 over x squared divided by 1 minus 9 over x squared
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Are you familiar with PEMDAS?

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3 years ago
Find the total surface area of a cuboidal room whose
denpristay [2]

Answer:

174cm^2

Step-by-step explanation:

Given data

L=9m

W=5m

H=3m

The formula for the total surface area of a cuboid is

SA=2lw+2lh+2hw

substitute

SA=2*9*5+2*9*3+2*3*5

SA= 90+54+30

SA= 174cm^2

Hence the surface area is 174cm^2

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3 years ago
A grain trader buys the following amounts from three suppliers:
prisoha [69]

Answer:

13,000 pounds

Step-by-step explanation:

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5 0
3 years ago
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Find dy /dx of x² - 2x + 5 - 6x
BaLLatris [955]

Answer:

Step-by-step explanation:

If y=x^2-2x+5-6x then

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\frac{dy}{dx}=2x-8

6 0
3 years ago
Hewwo!
ella [17]

Answer:

See Below.

Step-by-step explanation:

Please refer to the diagram below.

We are given that O is the center of the circle, and chords MN and RS are intersected a P. OP is the bisector of ∠MPR. And we want to prove that MN = RS.

We will construct segments OK and OJ such that it perpendicularly bisects MN and RS.

Since OP bisects ∠MPR, it follows that:

\displaystyle \angle JPO\cong \angle KPO

And since OK and OJ are perpendicular bisectors:

m\angle OKP=90^\circ \text{ and } m\angle OJP=90^\circ

Therefore:

\angle OKP\cong \angle OJP

By the Reflexive Property:

OP\cong OP

Therefore:

\Delta OKP\cong \Delta OJP

By AAS Congruence.

Hence:

OK\cong OJ

By CPCTC.

Recall that congruent chords are equidistant from the center.

Thus, by converse, chords that are equidistant from the center are congruent.

Therefore:

MN\cong RS

7 0
3 years ago
Read 2 more answers
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