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irga5000 [103]
3 years ago
7

they form a figure with a long side of 12f and a short side of 9f what is the diagonal of the figure be to make sure the base of

his tree house is a rectangle
Mathematics
1 answer:
Minchanka [31]3 years ago
7 0

The diagonal of a rectangular figure is an illustration of Pythagoras theorem

The diagonal of the figure is 15f

The given parameters are:

\mathbf{Long= 12f}

\mathbf{Short= 9f}

The diagonal is calculated using, the following Pythagoras theorem

\mathbf{Diagonal = \sqrt{Long^2 + Short^2}}

So, we have:

\mathbf{Diagonal = \sqrt{(12f)^2 + (9f)^2}}

Evaluate all squares

\mathbf{Diagonal = \sqrt{144f^2 + 81f^2}}

Evaluate like terms

\mathbf{Diagonal = \sqrt{225f^2}}

Take square roots

\mathbf{Diagonal = 15f}

Hence, the diagonal of the figure is 15f

Read more about diagonals at:

brainly.com/question/18983839

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Triangle ABC has vertices at (-3, -1), (-1, 2) and (6, 1). What is the perimeter of triangle ABC, rounded to the nearest tenth?
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Perimeter=19.9units

Why?

We can find the perimeter of any triangle adding the length of its sides. Since we are given 3 points, we need to calculate the length of the three sides of the triangle,  and then add them to know the perimeter of the triangle.

Let be the points:

A(-3,-1)

B(-1,2)

C(6,1)

<h3>- Distances</h3>

From A to B:

d(A,B)=\sqrt{(-1-(-3))^{2}+(2-(-1)^{2}}\\\\d(A,B)=\sqrt{(2)^{2}+(3)^{2}}=\sqrt{4+9}=3.61units

From A to C:

d(A,C)=\sqrt{6-(-3))^{2}+(1-(-1)^{2}}\\\\d(A,B)=\sqrt{(9)^{2}+(2)^{2}}=\sqrt{81+4}=9.22units

From B to C:

d(B,C)=\sqrt{6-(-1))^{2}+(1-2)^{2}}\\\\d(A,B)=\sqrt{(7)^{2}+(-1)^{2}}=\sqrt{49+1}=7.07units

Now, calculating the perimeter, we have:

Perimeter=d(A,B)+d(A,C)+d(B,C)=3.61units+9.22units+7.07units\\\\Perimeter=19.9units

Have a nice day!

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3 years ago
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