$8x-22=-60\qquad|\text{add 22 to both sides}\\\\8x-22+22=-60+22\\\\8x=-38\qquad|\text{divide both sides by 8}\\\\\dfrac{8x}{8}=\dfrac{-38}{8}\\\\x=-4.75$

7 0

3 years ago

2x+3y=4

garri49 [273]

Answer:

Option D.

Step-by-step explanation:

we have

$2x+3y=4$ -----> equation A

$2x-5y=-12$ -----> equation B

Solve the system by elimination

Multiply both sides equation A by -1

$-1(2x+3y)=-1(4)$

$-2x-3y=-4$ -----> equation C

Adds equation C and equation B

$-2x-3y=-4\\2x-5y=-12\\------\\-3y-5y=-4-12\\-8y=-16\\y=2$

<em>Find the value of x</em>

substitute the value of y in either equation

$2x+3(2)=4\\2x+6=4\\2x=-2\\x=-1$

The solution is the point (-1,2)

In this problem Option A,B and C are correct

The option D not result in a system with a pair of opposite terms

because

Multiply both sides of equation B by -3

$-3(2x-5y)=-3(-12)$

$-6x+15y=36$ -----> equation C

Multiply both sides of equation A by 5 $5(2x+3y)=5(4)$

$10x+15y=20$ ----> equation D

equation C and equation D not have a pair of opposite terms

5 0

3 years ago