Answer:
Step-by-step explanation:
1. Move the 6 to the other side: x^2 +4x =6
2. Square half the coefficient of the x term: (4/2)^2 = 4
3. Add this 4, and then subtract this 4, from x^2 + 4x:
x^2 +4x + 4 - 4 =6
4. Rewrite this perfect square as the square of a binomial:
(x + 2)^2 - 4 = 6
5. Add 4 to both sides: (x + 2)^2 = 10
6. Find the sqrt of both sides: x + 2 = √
Number 1 is C.
Number 2 is C.
Did you need all of them?
That’s the answer and i showed the work hoped this helped!!!
Answer:
Step-by-step explanation:
we have
Adds the terms
Group terms that contain the same variable
Combine like terms
where
therefore
f(x) being even means
f(x) = f(-x)
So the zeros come in positive and negative pairs. If there are an odd number of intercepts like there are here, it's because one of them is x=0 which is its own negation.
Given zero x=6 we know x=-6 is also a zero.
So we know three zeros, and know the other two zeros are a positive and negative pair.
The only choice with (-6,0) and (0,0) is A.
Choice A
