Answer:
I don't think much would change more animals would have lot of food and we would have lot of air
0.1 M solution of a disaccharide solution will contain 2000 monosaccharide molecules.
<h3>What are monosaccharides?</h3>
Monosaccharides, also known as simple sugars are the simplest monomers of carbohydrates which may either be 3 carbon, 4 carbon, 5 carbon, 6 carbon or 7 carbo compounds.
There are two types of monosaccharides;
- aldoses sugars, e.g. glucose, and
- ketose sugars e.g. fructose.
When two monosaccharides are linked together by glycosidic bonds to form a single compound, the compound formed is called a disaccharide.
Considering the give question:
Suppose a 0.1M solution of a monosaccharide contains 1000 monosaccharide molecules. How many monosaccharide molecules would be in a 0.1 M solution of a disaccharide.
The number of monosaccharides molecules present in the 0.1 M solution of a disaccharide is determined as follows:
1 disaccharide molecule contains 2 monosaccharide molecules
0.1M solution of a monosaccharide contains 1000 monosaccharide molecules.
0.1 M solution of a disaccharide will contain 2 * 1000 monosaccharide molecules
0.1 M solution of a disaccharide will contain = 2000 monosaccharide molecules.
Learn more about monosaccharides and disaccharides at: brainly.com/question/731310
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Answer:
B. Different genes are expressed due to their environment.
Explanation:
I think it's this one because it makes the most sense, but I'm still not sure sorry
Answer:
if you f her she will let you get straight A+
Explanation:
ik becuase ive done it
Answer:
C)Parental: 41% Dr, 41% dR; recombinant: 9% DR, 9% dr.
Explanation:
The notation Dr/dR for genotypes means that one homologous chromosome has the alleles Dr and the other homologous chromosome has the alleles dR.
The heterozygous plant Dr/dR will produce 4 types of gametes: two identical to the chromosmes the individual has in its somatic cells (called parental), and two gametes which will be a mix of the alleles in the homologous chromosomes (called recombinant).
- Dr: parental
- dR: parental
- DR: recombinant
- dr: recombinant
To calculate the frequency of each type of gamete, we must use the formula:
Distance (map units) / 100 = frequency of recombination.
18 mu / 100 = 0.18.
The total frequency of recombination between the genes D and R is 0.18, but every time crossing over happens, two recombinant gametes are generated. Therefore, each recombinant gamete will have a frequency of 0.18/2=0.09 = 9%.
The frequency of parental gametes will be:
1 - frequency of recombinant gametes
1 - 0.18 = 0.82
But there are 2 parental gametes, so each of them will have a frequency of 0.82/2=0.41 = 41%.
