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pychu [463]
2 years ago
9

Please help meee i need asap

Mathematics
2 answers:
AlladinOne [14]2 years ago
8 0
Look it up I have no idea
NARA [144]2 years ago
7 0

Answer:

WTH is that bro, If I had to answer this between a life or death situation I'd die

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Plz answer number 3 thx so much
nataly862011 [7]
The answer is isosceles and i think it's acute
6 0
2 years ago
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A swimming pool is to be drained. The pool is shaped like a rectangular prism with length 30 ft, width 18 ft, and depth 4 ft. Su
Licemer1 [7]

Answer:

10 hours (I am not positive)

Step-by-step explanation:

We first want to find the volume of pool which is 30 x 18 x 4 = 2160.

Then you are going to divide by 216 to find how many hours it takes to drain the whole pool. (I'm not that big of an expert)

4 0
2 years ago
9 less than k is 1. Solve the equation
Zinaida [17]

Answer:

the answer is 8

Step-by-step explanation:

9 - 8 = 1

  • Hope this helps
  • Brainliest plz
4 0
3 years ago
Read 2 more answers
Which of the equations below could be the equation of this parabola?
nirvana33 [79]

Answer:

 y=-4x^2  is the equation of this parabola.

Step-by-step explanation:

Let us consider the equation

y=-4x^2

\mathrm{Domain\:of\:}\:-4x^2\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:

\mathrm{Range\:of\:}-4x^2:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\le \:0\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:0]\end{bmatrix}

\mathrm{Axis\:interception\:points\:of}\:-4x^2:\quad \mathrm{X\:Intercepts}:\:\left(0,\:0\right),\:\mathrm{Y\:Intercepts}:\:\left(0,\:0\right)

As

\mathrm{The\:vertex\:of\:an\:up-down\:facing\:parabola\:of\:the\:form}\:y=a\left(x-m\right)\left(x-n\right)

\mathrm{is\:the\:average\:of\:the\:zeros}\:x_v=\frac{m+n}{2}

y=-4x^2

\mathrm{The\:parabola\:params\:are:}

a=-4,\:m=0,\:n=0

x_v=\frac{m+n}{2}

x_v=\frac{0+0}{2}

x_v=0

\mathrm{Plug\:in}\:\:x_v=0\:\mathrm{to\:find\:the}\:y_v\:\mathrm{value}

y_v=-4\cdot \:0^2

y_v=0

Therefore, the parabola vertex is

\left(0,\:0\right)

\mathrm{If}\:a

\mathrm{If}\:a>0,\:\mathrm{then\:the\:vertex\:is\:a\:minimum\:value}

a=-4

\mathrm{Maximum}\space\left(0,\:0\right)

so,

\mathrm{Vertex\:of}\:-4x^2:\quad \mathrm{Maximum}\space\left(0,\:0\right)

Therefore,  y=-4x^2  is the equation of this parabola. The graph is also attached.

7 0
3 years ago
If x = -6, which inequality is true?
lakkis [162]

Answer:

D

Step-by-step explanation:

8 0
2 years ago
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