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Angelina_Jolie [31]
3 years ago
12

A 95% confidence interval for the mean lead concentration in the urine of adult men working with lead (for smelting) is 8.22 to

11.98 micrograms per
liter (g/l). The numerical value of the margin of error for this confidence interval is ______Mg/1.
Mathematics
1 answer:
Komok [63]3 years ago
4 0
95% confidence = 2SD method.

11.98-8.22 = 3.76

3.76 / 2 = 1.88

ME= 1.88
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A scuba diver descends in the water at a rate of 23 1/2
Makovka662 [10]

The scuba diver's position relative to sea level after the 4.6 minutes is 5.1 ft.

Given:

A scuba diver descends in the water at a rate of 23 1/2  feet per minute for 2.6 minutes.

A scuba diver ascends at a rate of 28 feet per minute for 2 minutes after seeing a big fish.

To find :

The scuba diver's position relative to sea level after the 4.6 minutes.

Solution:

Rate of a scuba diver descending in the water for 2.6 minutes = R _1

R_1= 23\frac{1}{2}ft/min=\frac{47}{2} ft/min

Distance covered by a scuba diver in 2.6 minutes = d_1

d_1=R_1\times 2.6min=\frac{47}{2} ft/min\times 2.6 min=61.1 ft

Rate of a scuba diver ascending for 2 minutes = R _2

R_2= 28ft/min

Distance covered by a scuba diver in 2 minutes = d_2

d_2=R_2\times 2min=28 ft/min\times 2 =56 ft

The position of scuba diver after 4.6 minutes relative to sea level:

d_1-d_2=61.1 ft-56 ft=5.1ft

The scuba diver's position relative to sea level after the 4.6 minutes is 5.1ft.

Learn more about ascending rate and descending rate here:

brainly.com/question/1477877?referrer=searchResults

brainly.com/question/1072871?referrer=searchResults

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3 years ago
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Sladkaya [172]

Answer:

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Step-by-step explanation:

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3 years ago
State the two quantities that are being compared in each rate. Then calculate the equivalent unit rate.
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101.25 dollars are being compared to 9 hours. The unit rate is 11.25 dollars
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A researcher surveyed 220 residents of a city about the number of hours they
olga55 [171]

Answer:

Margin of error of 0.0485 hours.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

In this question:

\sigma = 0.35, n = 220

The margin of error is of:

M = z\frac{\sigma}{\sqrt{n}}

M = 1.96\frac{0.35}{\sqrt{200}}

M = 0.0485

Margin of error of 0.0485 hours.

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