D = { ..., - 3, - 2 , - 1 , 0, 1 , 2 , 3 , ...}
E = { 1, 4, 9, 16, 25 }
F = { 21, 23, 25, 27, 29 }
D ∩ E = { 1, 4, 9 , 16, 25 } - False ( A )
D ∩ F = {21, 23, 25 , 27, 29 } - False ( B )
E ∩ F = { 25 } - False ( D )
D ∩ ( E ∪ F ) = { 1, 4, 9 , 16, 21, 23, 25, 27, 29 } - False ( E )
Answer:
Correct statement is:
C ) D ∪ ( E ∩ F ) = { all whole numbers }
The answer is the third one
Invaluable means value less scan means scanning
