I would go with B. "parlor generals and field deserters"
Answer:
The second law of Thermodynamics relates the heat associated with a process to the entropy change for that process. DQ/dÈ=T(dS/dÉ)
205-49
I would round 49 to 50.
205-50=155
Now just add one back.
156
That makes it easier to solve.
I hope this helps!
~kaikers
Millimeters (mm) since it is a very small measurement
