The available options are:
Emails
Financial spreadsheets
User downloads
Databases
Answer:
User downloads
Explanation:
The correct answer is User downloads, this is because, the downloaded files are in cloud or another website memory or database, which serves as an alternative backup already. Thus, those downloaded files can still be recovered at later time when one needs to get the files back.
However, Emails, Financial spreadsheets and Databases, do not have any other place to retrieve them, because they are originally created and are yet to be uploaded to cloud or another website memory space to serves as alternative back up.
Answer:
# include <iostream>
#include<stdio.h>
using namespace std;
bool IsLeapYear(int y)
int main()
{
int y;
cout<<"Enter the Year to check Leap or Not"<<endl;
cin>>y;
IsLeapYear(int y);
getch();
}
bool IsLeapYear(int y)
{
if (y%4==0)
{
if (y%100==0)
{
if (y%400==0 )
{
cout<"The year is leap Year";
}
else
{
cout<<" The year is not Leap Year";
}
}
else
{
cout<<"The year is Leap Year" ;
}
}
else
{
cout<<"The year is not Leap Year";
}
}
Explanation:
In this program a function has been defined named as IfLeapYear, to check that whether the entered year is leap year or not. An year taken as integer data type named as y to enter the year to check. If the year is divisible by 4 but not divisible by 100 is the leap year. If the year is divisible by 4, divisible by 100 and also divisible by 400 is the century year and is also the leap year.
To check all the statements, Nested if-else conditions has been used to check multiple requirements of the leap year.
I type of shape, or a pointing index finger
Solution :
x = float_(input())
y = float_(input())
z = float_(input())
res1 = x**z
res2 = x**(y**z)
res3 = abs(x-y)
res4 = (x**z)**0.5
print('{:.2f} {:.2f} {:.2f} {:.2f}'.format(res1,res2,res3,res4))
Output is :
5.0
1.5
3.2
172.47 361.66 3.50 13.13
Update and measure those are the only understand answers
