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2 years ago

I need help im kinda stuck lol

Mathematics

2 answers:

balandron [24]2 years ago

7 0

The answer would be one two people hope I helped

anastassius [24]2 years ago

5 0

Answer:

1 person did as you can see

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In a sphere, if the radius is tripled, how much more volume do you have?

lilavasa [31]

If the radius is tripped, the volume will increase by 3^3 = 27 times.

Answer: 27 times

3 0

3 years ago

The longest side of the right triangle is 2 feet more than the middle side and the middle side is 1 foot less than twice the sho

Ket [755]

A right triangle's longest side is the hypotenuse
let x=longest, y=middle, and z=shortest
x=y+2
y=2z-1
therefore x=(2z-1)+2=2z+1
find z
z^2+y^2=x^2 by Pythagorean theorem
plug in x and y in terms of z
z^2+(2z-1)^2=(2z+1)^2
z^2+4z^2-4z+1=4z^2+4z+1
subtract the right-hand side's value from the left-hand side's
z^2-8z=0
z(z-8)=0
z=0, 8
z cannot be zero as the sides must have some value to it.
Therefore the shortest side is equal to 8

3 0

3 years ago

Shirley picked out a kite for $3.50. If she gave the family a ten dollar bill, what is the fewest number of bills and coins that

Aleonysh [2.5K]

Answer:

6.50

Step-by-step explanation:

$10.00-$3.50=$6.50

4 0

3 years ago

Suppose y is a positive integer.If x-(-y)=z will z be greater than x ?

alexira [117]

Answer:

Yes, z will be greater than x.

Step-by-step explanation:

Given expression is $x- (-y)=z \ for \ y \ is \ a \ positive \ integer.$

now let y = 2 and x = 1

Then, $x- (-y)=z \\1+2 = 3 \\\\$

where $z> x$ i.e. 3 > 1

on simplifying the given expression in terms of y

$y=z-x$

now suppose if x = 7 and z=3 then,

$y = (z-x) = (3-7) = (-4)$

which gives value of y in terms of negative integer which is not possible according to the given statement since y is a positive integer. Therefore, if y is a positive integer then z will be greater than x.

3 0

3 years ago

Read 2 more answers

Use the given data to construct a box plot and identify the 5-number summary. Eleven different second-year medical students at B

Galina-37 [17]

Answer:

$Min =120, Max= 150$

The first quartile can be calculated with this data:

130, 135, 140, 120, 130, 130

And the middle value is:

$Q_1 = \frac{140+120}{2}=130$

The median is the value in the 6th position from the dataset ordered and we got:

$Median= 135$

The third quartile can be calculated with this data:

135 140 140 143 144 150

And the middle value is:

$Q_3 = \frac{140+143}{2}=141.5$

The five number summary for this case:

Min. 1st Qu. Median Mean 3rd Qu. Max.

120.0 130.0 135.0 135.6 141.5 150.0

The boxplot is on the figure attached

Step-by-step explanation:

We have the following data given:

130, 135, 140, 120, 130, 130, 144, 143, 140, 130, 150

If we sort the values on increasing order we got:

120 130 130 130 130 135 140 140 143 144 150

The minimum and maximum are:

$Min =120, Max= 150$

The first quartile can be calculated with this data:

130, 135, 140, 120, 130, 130

And the middle value is:

$Q_1 = \frac{140+120}{2}=130$

The median is the value in the 6th position from the dataset ordered and we got:

$Median= 135$

The third quartile can be calculated with this data:

135 140 140 143 144 150

And the middle value is:

$Q_3 = \frac{140+143}{2}=141.5$

The five number summary for this case:

Min. 1st Qu. Median Mean 3rd Qu. Max.

120.0 130.0 135.0 135.6 141.5 150.0

The boxplot is on the figure attached

8 0

3 years ago