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Sever21 [200]
2 years ago
7

I need help im kinda stuck lol

Mathematics
2 answers:
balandron [24]2 years ago
7 0
The answer would be one two people hope I helped
anastassius [24]2 years ago
5 0

Answer:

1 person did as you can see

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By reporting only p-values, many scientific publications provide an incomplete story of their findings.
11Alexandr11 [23.1K]

Answer:

a.

Step-by-step explanation:

The p-value is a measurement of the likelihood that a difference observed is due to a random chance or a sampling error. In an alternative way, the p-value of a study represents the probability or area under distribution for obtaining more radical outcomes whenever the null hypothesis is true.

Any observable change is deemed to be addressed by sampling variability if the P-value is greater than the selected alpha level. A statistical test will nearly always show a substantial difference with a suitably big sample unless there is no impact at all when the effect size is exactly zero.

As a result, simply reporting the P-value alone for a study is insufficient to fully validate the results and findings of scientific publications.

3 0
3 years ago
A decimal and fraction between -4 and -3
Murrr4er [49]

Answer:

Step-by-step explanation:

-3.5 -3 1/2

3 0
4 years ago
Aratati ca A=ab+ba-aa-bb este pătrat perfect DAU FUNDA PLZZZZ
Nataly [62]

Answer:

Aratati ca numarul A=ab+ba-aa-bb este patrat perfect ( deasupra la ab ba aa bb este o linie orizontala) b)determinati nr ab astfel incat B=ab+5ab-126 sa fie patrat perfect ( deasupra la ab 5ab este o linie orizontala) c) aratati ca 25=3²+4² si 625=7²+24²

Step-by-step explanation:

english?

5 0
4 years ago
Which of the following are solutions to 2tanx/1-tan^2x=sqrt 3?
Tanya [424]

Answer:

A, D

Step-by-step explanation:

(\frac{2tanx}{1-tan^{2}x}) =\sqrt{3} (1)

Assume that tan x = y. Replace this into the equation (1), we have:

+) \frac{2y}{1-y^{2} } =\sqrt{3}

=> 2y = \sqrt{3}  . (1 -y^{2} ) =- \sqrt{3} .y^{2}  + \sqrt{3}

=> \sqrt{3} .y^{2}  + 2y - \sqrt{3} = 0

=> \sqrt{3} . y^{2} - 1.y + 3.y - \sqrt{3} =0

=> (\sqrt{3} . y.y - 1.y) + (\sqrt{3}.\sqrt{3}  .y - \sqrt{3}) =0

=> y.(\sqrt{3} y - 1) + \sqrt{3} (\sqrt{3} y - 1) = 0

=> (y + \sqrt{3} ).(\sqrt{3} .y -1)=0

=> y + \sqrt{3} = 0 or \sqrt{3} y -1 =0

If y + \sqrt{3} = 0

=> y = - √3

=> tan x = - √3

=> x = \frac{2\pi }{3} + n.\pi with n is an integral

If \sqrt{3} y -1 =0

=> y = 1/√3

=> tan x = 1/√3

=> x = \frac{\pi }{6} + n.\pi n is an integral

So that A, D are answers.

3 0
3 years ago
Read 2 more answers
The sum of two numbers is 85. The second number is 4 more than 2 times the first number. Let x represent the first number and le
Thepotemich [5.8K]
No need to guess, just math!

x + y = 85, so x = 85 - y
Let’s substitute this in the second equation

y = 2(85 - y) + 4
y= 170 - 2y + 4
3y = 174

y = 58

x = 85 - 58 = 27
[third option from the top]
7 0
2 years ago
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