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FinnZ [79.3K]
3 years ago
11

A) Draw the graph of y= 4x - 1 on the grid

Mathematics
1 answer:
UkoKoshka [18]3 years ago
4 0

9514 1404 393

Answer:

  see attached for a graph

  x = 0.5 when y = 1

Step-by-step explanation:

The graph has a y-intercept of -1, which is halfway between 0 and -2. It goes up 4 units (2 vertical grid spaces) for 1 unit to the right (1 horizontal grid space). It seems to cross y = 1 at about x = 1/2.

x = 1/2 when y = 1.

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Tony scored n points in the first basketball game of the season. The expression below represents the total number of points that
julsineya [31]
Add the n terms together n + 2n + 2n = 5n
Add the numbers together - 3

The answer is 5n - 3 or D <<<=====
3 0
4 years ago
Evaluate each expression |18|
igor_vitrenko [27]
That equals 18 since the distance from zero is 18.


Hope i'm the brainliest!
4 0
4 years ago
A cube-shaped box has a volume of
Gala2k [10]

Answer:

B.

Step-by-step explanation:

<em>Volume for a cube is </em>

V= s^{3}  <em>s = side length</em>

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4 0
3 years ago
The total cost of renting a banquet hall is a function of the number of hours the hall is rented. The owner of the banquet hall
madam [21]

Answer:

It would be $390 for the 4 hours and the cleaning fees. And the slope would be -13 if you are going from 12 to 7 but would be 13 if you are going from 7 to 12...

Step-by-step explanation:

4 0
3 years ago
the length of a rectangle is 8 more than the width. the area is 273 square inches. find the length and width of the rectangle
GREYUIT [131]
273 = 1·273 = 3·91 = 7·39 = 13·21

The factors that differ by 8 are 13 and 21.

The length is 21 inches; the width is 13 inches.


_____
If you're going to write an equation for width (w), you can write it as
  w(w+8) = 273
and simplify it to
  w² +8w -273 = 0
Solving this by factoring requires you find the factors of 273 that differ by 8, as above.

You can also solve by completing the square or using the quadratic formula. Those methods will tell you w is either of -21 or 13. Only the positive solution is applicable.

Another method I use mentally is to think of the equation in terms of the average of length and width (x). Then the area is
  (x-4)(x+4) = 273
  x² -16 = 273 . . . . . this is a much easier quadratic to solve
  x² = 289
  x = 17 . . . . . . . . you know this because you have the squares of small numbers memorized.
Then the dimensions are 17-4 = 13, and 17+4 = 21.
5 0
3 years ago
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