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3 years ago

Which graph shows the correct solution to the inequality below?

Mathematics

2 answers:

Assoli18 [71]3 years ago

6 0

Answer:

Third Option

Step-by-step explanation:

3x + 18 > 6x - 9

We have to find the value of x for this

Subtract 18 from both sides to leave 3x alone

3x > 6x - 27

Subtract 6x from both sides to be able to find the value of x

-3x > -27

Divide by -3 on both sides

x > 9

The answer would be the third option, since X is anything greater than 9

lorasvet [3.4K]3 years ago

6 0

The second one is the answer

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Factor completely <br> 4x^2 + 24x - 64

lara31 [8.8K]

First see you can factor out 4. What is left is x^2 + 6x - 16.
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4(x+8)(x-2)

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A wire b units long is cut into two pieces. One piece is bent into an equilateral triangle and the other is bent into a circle.

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1. Divide wire b in parts x and b-x.

2. Bend the b-x piece to form a triangle with side (b-x)/3

There are many ways to find the area of the equilateral triangle. One is by the formula A= $\frac{1}{2}sin60^{o}side*side= \frac{1}{2} \frac{ \sqrt{3} }{2} (\frac{b-x}{3}) ^{2}= \frac{ \sqrt{3} }{36}(b-x)^{2}$
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Another way is apply the formula A=1/2*base*altitude,
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3. Let x be the circumference of the circle.

$2 \pi r=x$

so $r= \frac{x}{2 \pi }$

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be the function of the sum of the areas of the triangle and circle.

5. f(x) is a minimum means f'(x)=0

f'(x)= $\frac{ -\sqrt{3} }{18}b+ \frac{ \sqrt{3} }{18}x+\frac{1}{2 \pi } x$ =0

$\frac{ -\sqrt{3} }{18}b+ \frac{ \sqrt{3} }{18}x+\frac{1}{2 \pi } x=0$

$(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) x=\frac{ \sqrt{3} }{18}b$

$x= \frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }$

6. So one part is $\frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }$ and the other part is b- $\frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }$

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<h3>Volume of a rectangular prism</h3>

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