If Tom has 3 different sweaters, and 5 different pairs of pants, how many different combinations could he wear?

Mathematics

1 answer:

Vladimir [108]3 years ago

7 0

Check the tree diagram in the picture.

Tom could pick Pants 1 (P1), then Sweater 1, 2 or 3. So 3 combinations

Similarly if we picked P2, P3, P4 or P5 we would have 3 combinations per each.

In total we have 5*3=15 different combinations.

Answer:15

You might be interested in

Find the area of a parallelogram if a base and corresponding altitude have the indicated lengths. Base 1 1/2 feet, altitude 6 in

Butoxors [25]

Area of a parallelogram = A =base*height

so in this case is just (1½)(6).

first off let's convert the mixed fraction to "improper",

$\bf \stackrel{mixed}{1\frac{1}{2}}\implies \cfrac{1\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{3}{2}}
\\\\\\
\cfrac{3}{2}\cdot 6\implies \cfrac{18}{2}\implies 9$

3 0

3 years ago

Read 2 more answers

An experienced carpenter can frame a house twice as fast as an apprentice. Working together, it takes the carpenters 2 days. How

AleksAgata [21]

Answer:

6 days

Step-by-step explanation:

Let the time taken by Carpenter working alone = $C$ days

Then time taken by apprentice alone = Twice as that of taken by Carpenter = 2 $C$ days

Time taken working together = 2 days

Work done in one day working together = $\frac{1}{2}$

Work done in one day by Carpenter working alone = $\frac{1}{C}$

Work done in one day by apprentice working alone = $\frac{1}{2C}$

Work done in one day by Carpenter working alone + Work done in one day by Carpenter working alone = $\frac{1}{C}$ + $\frac{1}{2C}$ = Work done in one day working together = $\frac{1}{2}$

$\dfrac{1}{C}+\dfrac{1}{2C}=\dfrac{1}{2}\\\Rightarrow \dfrac{2+1}{2C}=\dfrac{1}{2}\\\Rightarrow C = 3\ days$