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BartSMP [9]
2 years ago
12

Determine the domain and range of the given function.

Mathematics
2 answers:
Nina [5.8K]2 years ago
4 0

Using function concepts, it is found that:

  • The domain of the function is <u>all real numbers</u>.
  • The range of the function is <u>all real numbers greater than or equal to -2.</u>

The domain of a function is the <u>set that contains all possible input values</u>. In a graph, it is the values assumed by the <u>x-axis</u>.

  • In this graph, x assumes all values from negative infinity to positive infinity, thus the domain is all real numbers.

The range of a function is the <u>set that contains all possible input values</u>. In a graph, it is the values assumed by the <u>y-axis</u>.

  • In this graph, y assumes values from -2 to positive infinity, thus the range is all real numbers greater than or equal to -2<u>.</u>

A similar problem is given at brainly.com/question/2145599

myrzilka [38]2 years ago
3 0

<em> </em><em>here </em><em>is </em><em>your</em><em> answer</em><em> </em><em>refer</em><em> to</em><em> the</em><em> attachment</em>

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A side of the triangle below has been extended to form an exterior angle of 159°. Find the value of x
Blababa [14]

Answer:

Find the the angle by subtracting 159 from 180 that’s your answer= 21 degrees

Step-by-step explanation:

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6 0
3 years ago
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Please help me with this trigonometry question. Brainliest available.
faltersainse [42]
Considering the angle a by cosine rule
11^2 =7 ^2 +15^2 - 2(7)(15)cos(a)
When you do the maths,
Cos(a) =153/210 =0.729
a= cos inverse of 0.729
a=43 degrees


Considering angle b
7^2=15^2 +11^2 -2(11)(15) cos(b)
This will result in cos(b) =297/330=0.9
b= cos inverse of 0.9 = 25.8 degrees


Considering angle c
15^2=7^2 +11^2 - 2(11)(7) cos(c)
Cos(c) will be = -55/154 = -0.357
c= cos inverse of -0.357=110.9

Comparing the angles a,b and c,
C is the largest size in the triangle with an angle of 110.9 degrees

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5 0
2 years ago
12. Find the measure of each interior angle of triangle QRT.
Veseljchak [2.6K]

Answer:

\angle QRT=125.6\°

\angle RTQ=6.4\°

\angle TQR=48\°

Step-by-step explanation:

It is important to remember that, by definition, the measure of an exterior angle of a triangle is equal to the sum of the measures of the two non-adjacent interior angles.

In this case we can idenfity that the angle 17x is an exterior angle of the triangle QRT. Then:

17x=\angle RTQ+\angle TQR

Where:

\angle RTQ=2x\\\\\angle TQR=48\°

Substituting values and solving for "x", we get:

17x=2x+48\\\\17x-2x=48\\\\15x=48\\\\x=3.2

Then:

17x=17(3.2)=54.4\°\\\\\\\angle RTQ=2(3.2)=6.4\°

The sum of the interior angles of a triangle is 180°, therefore:

\angle QRT+\angle RTQ+\angle TQR=180

Solving for \angle QRT, we get:

\angle QRT=180-48-6.4=125.6\°

8 0
3 years ago
Help me I really need it
yulyashka [42]

24/4=6

so 6 pieces on each side, since a rectangle is a square


8 0
3 years ago
How do I solve 2x+3y=7, x-y=1
Fittoniya [83]
<span>2x+3y=7
x-y=1

</span>2x+3y=7
x=1+y

2*(1+y)+3y=7
x=1+y

2+2y+3y=7
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5y=5       |(:5)
x=1+y

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CHECK:
2x+3y=7
x-y=1

2*2 + 3*1 = 7     

x-y = 1
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5 0
3 years ago
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