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3 years ago

What is conventional sign and symbols?

Geography

2 answers:

frozen [14]3 years ago

7 0

Answer:

tu bor kyu hö rahi hai meh hu na-,- tere liye(≧▽≦)(≧▽≦)

$\: \: \:$

Readme [11.4K]3 years ago

5 0

Answer:

Conventional symbols are widely accepted signs or sign systems which signify an idea or concept. They represent different features on a map and are not drawn to scale. They are important because: Symbols can be used to depict features like cities, roads and railways.

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The Earth’s population has increased by more than __________ people in the last 100 years. A. 300 million B. 7 billion C. 6.9 bi

Triss [41]

the world's current population is 7.3 billion and the world population in 1915 was 1.8 billion. The increase over the past century is 7.3 billion - 1.8 billion = 5.5 billion. So, the correct answer would be "more than 5 billion" (option D).

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4 years ago

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True or false modern mali is unique due to the blending of islam and black african traditions from the middle ages and the rich

NikAS [45]

Yes, this is true!
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3 years ago

What body of water would you be on at 42° S, 112° w?||

Gre4nikov [31]

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3 years ago

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The content of carbon di oxide in the atmosphere keeps on fluctuating. Explain

nevsk [136]

Answer:

Plants play a large factor in fluctuating levels of CO2 within the atmosphere. Plants, through photosynthesis, convert CO2 gas into sugars and O2 gas powered through sunlight. In different seasons, the plants become active or deactivate and can undergo different amounts of photosynthesis. For example, during the winter, CO2 is very high, as many plants are not undergoing photosynthesis and cannot convert the CO2 into O2. But in spring, CO2 is drastically lowered as they are far more active in converting the atmospheric gas.

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2 years ago

3. A space vehicle is traveling at 4300 km/h relative to Earth when the exhausted rocket motor (mass 4m) is disengaged and sent

kvv77 [185]

Answer: Vce= 4234.4km/hr or 1180m/s

Explanation:

Mass of rocket motor Mr= 4m

Mass of control module Mc= m

Initial velocity of spaceship relative to earth Vs= 4300km/hr

Final velocity of command module relative to the rocket motor Vrc = 82km/hr

Total mass of spaceship M= 4m+m= 5m

Using law of conservation of momentum;

MVs= MrVre + McVce eqn1

Vre = Vrc+Vce eqn2

Where Vce is velocity of control room relative to the earth and Vre is velocity of rocket motor relative to the earth

Substituting eqn2 to eqn1, we have.

MVs= Mr(Vrc+Vce) +McVce

MVs= MrVrc+MrVce+McVce

Making Vce the subject of formula.

Vce = (MVs-MrVrc)/(Mc+Mr)

Substituting the values we have,

Vce = (5m×4300km/hr - 4m×82km/hr)/ (m+4m)

Vce = 21172m/5m

Vce= 4234.4km/hr or 1180m/s

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3 years ago