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Softa [21]
3 years ago
11

Here are six number cards.

Mathematics
1 answer:
steposvetlana [31]3 years ago
8 0

Answer:

well...............................................................i think i just st0le points

Step-by-step explanation:

sowwy

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A rectangle is 32m by 8m is similar to a rectangle 4m by x m.
Flauer [41]

Answer:

x = 1

Step-by-step explanation:

x/4 = 8/32

x = 1

Best Regards!

5 0
3 years ago
Read 2 more answers
What is the product?<br> (-2x - 3y ?) (-4x-3)
statuscvo [17]

Answer:

8x²+6x+12xy+9y

Step-by-step explanation:

⇒(-2x - 3y)(-4x - 3)

⇒(-2x × -4x)+(-2x × -3)+(-3y × -4x)+(-3y × -3)

⇒8x²+6x+12xy+9y

4 0
3 years ago
Six rolls of fabric are used for making five dresses equally.
Kryger [21]

Answer:

1.2 rolls

Step-by-step explanation:

6 rolls=5 dresses

1.2 rolls             =1 dress

hope i helped:)

7 0
2 years ago
Consider a sample with data values of 27, 25, 20, 15, 30, 34, 28, and 25. Compute the range, interquartile range, variance, and
Valentin [98]

So we have a set of integers,

X=\{15,20,25,25,27,28,30,34\}

And we need to compute some stats.

First the range,

The range of data set is difference between the maximum and the minimum of the data set.

So the minimum is 15 and maximum is 34 therefore the range is 34 - 15 = 19.

Second the interquartile range,

The interquartile range of data set is the difference of the first and third quartiles.

First quartile is the value separating the lower quarter and higher three - quarters of the set. The first quartile is computed by taking median of the lower half of the sorted set. This is 15, 20, 25, 25 and it's median is 22.5

Third quartile is therefore the median of 27, 28, 30, 34 which is 29.

Next up, variance.

The variance of set measures how much data is spread out. For data set x_1,\dots, x_n with an average a,

\mathsf{var}(X)=\Sigma_{i=1}^{n}\dfrac{(x_i-a)^2}{n-1}

So first compute the average value which is actually a mean,

a=\dfrac{1}{2}\Sigma_{i=1}^{n}a_i

The sum \Sigma_{i=1}^{n}a_i of numbers in set is 204.

Divide this by number of elements in the set (8).

a=\dfrac{204}{8}=25.5

Then compute the variance,

\mathsf{var}(X)=\dfrac{\Sigma_{i=1}^{n}(x_i-a)^2}{n-1}\approx\boxed{34.57}

And finally standard deviation,

Since have computed variance the standard deviation is nothing too hard. It's defined as a square root of variance,

\mathsf{sde}(X)=\sqrt{\dfrac{\Sigma_{i=1}^{n}(x_i-a)^2}{n-1}}=\sqrt{34.57}\approx\boxed{5.88}

Hope this helps.

r3t40

6 0
2 years ago
Simplify the expression to a + bi form
Gnesinka [82]

-√4 + √(-48) + √121 + √(-108)

= -√(2²) + √(-1 • 3 • 4²) + √(11²) + √(-1 • 2² • 3³)

= -2 + 4√3 i + 11 + 6√3 i

= 9 + 10√3 i

4 0
2 years ago
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