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kaheart [24]
3 years ago
13

Solve the simultaneous equation 5x-4y=10. X+2y=9

Mathematics
1 answer:
professor190 [17]3 years ago
4 0

Step-by-step explanation:

<h2>using ELIMINATION method</h2>

10x-8y=20

4x+8y=36

14x=56

x=56/14

x=4

<h3>NOW FOR Y.</h3>

10(4)-8y=20

40-8y=20

-8y=20-40

-8y=-20

y=-20/-8

y=2.5

<h2>MARK ME BRAINLIEST PLS!!</h2>
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82 tens is the same as what?
Feliz [49]
82 tens in the same thing as 820 because if you multiply 82 by 10 you get 820
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3 years ago
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A boat traveled 153 miles downstream and back. The trip downstream took 9 hours. The trip back took 17 hours. What is the speed
fgiga [73]

Speed of boat in still water is 13 miles per hour and speed of current is 4 miles per hour

<h3><u><em>Solution:</em></u></h3>

Let  s  =  the speed of the boat in still water in miles/hour

Let  c  =  the speed of the current in miles/hour

<em><u>Formula to remember:</u></em>

If the speed of a boat in still water is s miles/hr and the speed of the current is c miles/hr, then:

Speed downstream = (s + c) miles per hour

Speed upstream = (s - c) miles per hour

<em><u>Given:</u></em>

boat traveled 153 miles downstream and back

distance for downstream = 153 miles

distance for upstream = 153 miles

time taken for downstream = 9 hours

Time taken for upstream = 17 hours

<em><u>The relation between speed, distance and time is given as:</u></em>

distance = speed \times time

<em><u>For downstream:</u></em>

153 = (s + c) \times 9

s + c = \frac{153}{9} = 17

s + c = 17 ------- eqn 1

<em><u>For upstream:</u></em>

153 = (s - c) \times 17\\\\s - c = \frac{153}{17} = 9

s - c = 9 ------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2 to find values of "s" and "c"</u></em>

Add eqn 1 and eqn 2

s + c = 17

s - c = 9

(+) -------------

2s = 26

<h3>s = 13</h3>

Substitute s = 13 in eqn 1

13 + c = 17

c = 17 - 13 = 4

<h3>c = 4</h3>

Thus the speed of boat in still water is 13 miles per hour and speed of current is 4 miles per hour

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Naily [24]
I think it would be A
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A circle with a radius of 15 yards contains a sector with an area of 609 yde. Find the measure of
kondaur [170]

Answer: 310.3° or 5.41 radians.

Step-by-step explanation:

The area of a circle of radius R is calculated as:

A = pi*R^2

Now, if we have a sector of an angle θ degrees, the area of that sector is:

A = (θ/360°)*pi*R^2

In this case, we know that:

R = 15yd

And the area of the sector is 609 yd^2

Then we can replace these two values in the equation to get:

609yd^2  =(θ/360°)*3.14*(15yd)^2

(609yd^2)*360°/(3.14*(15yd)^2) = θ = 310.3°

And we want the angle also in radians.

We know that:

3.14 rad = 180°

(3.14 rad/180°) = 1

Then:

310.3° = 310.3°*(3.14 rad/180°) = (310.3°/180°)*3.14 rad = 5.41 radians.

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The percentile of 1.2 equals?
laila [671]

It’s 0.3 because that’s the answer

6 0
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