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2 years ago

Name the smallest even number divisible by 6 and 9.

Mathematics

1 answer:

Step2247 [10]2 years ago

5 0

Answer:

Step-by-step explanation:

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A $1,200 Mac is on sale for 15% off. How much was the discount?

Fudgin [204]

Answer: The discount is $180, and the price with the discount is $1,020.

Step-by-step explanation: Multiply 1,200 times .15 to get the discount, or how much you get off. Then subtract the answer, which is $180, from the original price, to get $1,020. This is the price with the discount.

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2 years ago

WILL MARK BRAINLEST TO THE CORRECT ANSWER (55 POINTS!!!)

nikitadnepr [17]

Answer:

y=20

Step-by-step explanation:

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2 years ago

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shutvik [7]

Answer:

( 2, 1 )

Step-by-step explanation:

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2 years ago

Read 2 more answers

I forgot how to do this n they didn’t put an example help me lol

lyudmila [28]

Answer:

60 $m^2$

Step-by-step explanation:

First, find the area of the square as it the missing piece wasn't missing.

8 x 9 = 72 $m^2$

Then, find the area of the missing section.

3 x 4 = 12 $m^2$

Finally, subtract 12 $m^2$ from 72 $m^2$ and you get 60 $m^2$

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2 years ago

A street light is mounted at the top of a 15-ft-tall pole. A man 6 ft tall walks away from the pole with a speed of 4 ft/s along

mina [271]

Answer:

The tip of the man shadow moves at the rate of $\frac{20}{3} ft.sec$

Step-by-step explanation:

Let's draw a figure that describes the given situation.

Let "x" be the distance between the man and the pole and "y" be distance between the pole and man's shadows tip point.

Here it forms two similar triangles.

Let's find the distance "y" using proportion.

From the figure, we can form a proportion.

$\frac{y - x}{y} = \frac{6}{15}$

Cross multiplying, we get

15(y -x) = 6y

15y - 15x = 6y

15y - 6y = 15x

9y = 15x

y = $\frac{15x}{9\\} y = \frac{5x}{3}$

We need to find rate of change of the shadow. So we need to differentiate y with respect to the time (t).

$\frac{dy}{t} = \frac{5}{3} \frac{dx}{dt}$ ----(1)

We are given $\frac{dx}{dt} = 4 ft/sec$ . Plug in the equation (1), we get

$\frac{dy}{dt} = \frac{5}{3} *4 ft/sect\\= \frac{20}{3} ft/sec$

Here the distance between the man and the pole 45 ft does not need because we asked to find the how fast the shadow of the man moves.

7 0

2 years ago