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2 years ago

What expressions cannot be factored?

Mathematics

1 answer:

BartSMP [9]2 years ago

7 0

Answer:

A polynomial with integer coefficients that cannot be factored into polynomials of lower degree , also with integer coefficients, is called an irreducible or prime polynomial .

Step-by-step explanation:

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Find the x-intercept and y-intercept of the line. 2x-6y=6

scoundrel [369]

Answer:

x-intercept: (3,0)

y-intercept: (0,−1)

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3 years ago

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What is the length of a side cube with a volume of 729m3

shusha [124]

27 because said a cube teacher told me to do s time s that means square•square

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4 years ago

what is the smallest number to be subtracted from 9610,so that the remainder will be a perfect square

Romashka-Z-Leto [24]

Answer:

Hello,

Answer 6

Step-by-step explanation:

$\sqrt{9610} =98,03060...\\\\ENT(\sqrt{9610})=98\\\\9610-98^2=9610-9604=6\\\\$

The smallest number to be susbtracted is 6

4 0

3 years ago

A rectangle has its vertices at (-4, -3), (-4,7), (1,7), (1, -3). What part, in percent, of the rectangle is located in Quadrant

Rasek [7]

Consider the attached figure. The whole rectangle is ABCD, while AEGF is the part located in the third quadrant. In fact, this quadrant is composed by all the points with both coordinates negative.

To answer the question, let's compute the area of the two rectangles and see what part of ABCD is AEGF.

A and B have the same x coordinate, so the length of AB is given by the absolute difference of their y coordinates:

$\overline{AB} = |A_y-B_y| = |-3-7| = |-10| = 10$

Similarly, but exchanging the role of x and y, we compute the length of BC:

$\overline{BC} = |B_x-C_x| = |-4-1| = |-5| = 5$

So, the area of the rectangle is $\overline{AB} \cdot \overline{BC} = 10\cdot 5 = 50$

The same procedure allows us to compute width and height of the sub-rectangle in the third quadrant:

$\overline{AE} = |A_y-E_y| = |-3-0| = |-3| = 3$

$\overline{EG} = |E_x-G_x| = |-4-0| = |-4| = 4$

So, the area of the portion located in the third quadrant is $\overline{AE} \cdot \overline{EG} = 3\cdot 4 = 12$

This means that the ratio between the two area is

$\cfrac{\text{area }AEGF}{\text{area }ABCD} = \cfrac{12}{50}$

If we want this ratio to be a percentage, just make sure that the denominator is 100:

$\cfrac{12}{50} = \cfrac{12}{50}\cdot \cfrac{2}{2} = \cfrac{24}{100} = 24\%$

3 0

3 years ago

Number four please help. Whatever helps gets a Brainly award

pashok25 [27]

29.99 + 35.00 + 3.25 + 3.25 = 71.49

125.00 - 71.49 = 53.51

53.51 ÷ 22.50 = 2.4 = 2

She can buy 2 pairs of shoes.

Hope this helps!!
~Kiwi

8 0

4 years ago