Answer:
Step-by-step explanation:
R=50+20t, B=150-20t they will be the same height when
50+20t=150-20t
50+40t=150
40t=100
t=2.5, usingvthis value for t in either original equation will give you the height.
h=50+20(2.5)
h=100m
x+2 > 10 solves to x > 8 after we subtract 2 from both sides
So set A is the set of real numbers that are larger than 8. The value 8 itself is not in set A. The same can be said about 5 as well.
Set B is the set of values that are larger than 5 since 2x > 10 turns into x > 5 after dividing both sides by 2. The value x = 5 is not in set B since x > 5 would turn into 5 > 5 which is false. The values x = 6, x = 8, and x = 9 are in set B.
----------------
Summarizing everything, we can say...
5 is not in set A. True
5 is in set B. False
6 is in set A. False
6 is not in set B. False
8 is not in set A. True
8 is in set B. True
9 is in set A. True
9 is not in set B. False
Answer:
x = -203/23
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
y = -23(x + 9) + 4
y = 0
<u>Step 2: Solve for </u><em><u>x</u></em>
- Substitute in <em>y</em>: 0 = -23(x + 9) + 4
- [Subtraction Property of Equality] Subtract 4 on both sides: -4 = -23(x + 9)
- [Division Property of Equality] Divide -23 on both sides: 4/23 = x + 9
- [Subtraction Property of Equality] Subtract 9 on both sides: -203/23 = x
- Rewrite: x = -203/23
$682.11
749.99•15% or .15=112.50
So 749.99-112.50=$637.49 and
637.49 • 7% or .07= 44.62 and
44.62+637.49=$682.11
ANSWER
EXPLANATION
The given function is a piecewise defined function.
is the y-value that corresponds to
To determine that y-value, we need to trace from
to where it meets the graph.
We then trace to the y-axis to determine the corresponding y-value as shown in the diagram.
From the graph, we can see that this x-value corresponds to a y-value of
This implies that, when
Therefore
See graph.
