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Pani-rosa [81]
2 years ago
6

The tension t in a spring varies directly with the distance d the spring is stretched. If the

Mathematics
1 answer:
yarga [219]2 years ago
7 0

Answer:

t = 21d

Step-by-step explanation:

Here tension and distance are denoted t by d  and  respectively. Since  t varies directly with d , then the relation between  t and d is k=td Given that, for the tension 42 pounds, the spring is stretched 2 inches. Substituting  t = 42 and d= 2 into  t = kd find the value of k . Therefore,

42= K (2)

K=\frac{42}{2}

K= 21

Thus the relationship is t = 21d

(Hope this helps can I pls have brainlist (crown)☺️)

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