The center of a circle whose equation is x^2 +y^2 – 12x – 2y +12 = 0 is (6,1)
<h3>Equation of a circle</h3>
The standard equation of a circle is expressed as:
x^2 + y^2 + 2gx + 2fy + c = 0
where:
(-g, -f) is the centre of the circle
Given the equations
x^2 +y^2 – 12x – 2y +12 = 0
Compare
2gx = -12x
g = -6
Simiarly
-2y = 2fy
f = -1
Centre = (6, 1)
Hence the center of a circle whose equation is x^2 +y^2 – 12x – 2y +12 = 0 is (6,1)
Learn more on equation of a circle here: brainly.com/question/1506955
Answer:
The answer is <u>B.) $16</u>
Step-by-step explanation:
Multiply 16$ by 6 which resembles half a year. You will get $96 from 16*6
10 x 40 = 400 so the answer is 400 pieces of chalk.
Answer:
270 cubic inches
Step-by-step explanation:
first you multiply 9 times 5 which equals 45 and then you multiply 45 by 6 to get 270. (for volume its length times width times height)
Lines A and B are parallel. Lines A and B apre perpendicular to Line C.
Change all of the lines from standard form to slope-intercept.
Line A: y = 4/3x + 2/3
Line B: y = 4/3x + 2
Line C: y = -3/4x + 1
Since A and B have the same slope they are parallel. C has a negative reciprocal so it's perpendicular.
