Please help with one of these

A car going 72.0 km/h (20.0 m/s) slows down to 36.0 km/h (10.0 m/s) in 5.00 seconds. Calculate the acceleration in

Vlada [557]

Answer:

-2 m/s^2

Step-by-step explanation:

Just as you would calculate the velocity when a body moves from point A to point B in a time T, we are going to calculate the acceleration as the difference of the velocities (final - initial) and divide it by the time it took:

Velocity_final = 10 m/s

Velocity_initial = 20 m/s

Time = 5 s

acceleration = (Velocity_final - Velocity_inital)/Time

= (10 m/s - 20 m/s)/5 s

= (-10 m/s) / 5s

= -2 m/s^2

The acceleration in m/s^2 is -2

6 0

3 years ago

I have to turn this in at 5:00 pls help!!!

Georgia [21]

It would be 2/5

There’s 12 bass fish and 30 fish overall

Which equals:
12/30

And then if you simplify 12/30 you get 2/5

3 0

3 years ago

A professor would like to test the hypothesis that the average number of minutes that a student needs to complete a statistics e

professor190 [17]

Answer:

$\chi^2 =\frac{15-1}{25} 16 =8.96$

The degrees of freedom are given by:

$df = n-1 = 15-1=14$

The p value for this case would be given by:

$p_v =P(\chi^2$

Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not ignificantly lower than 5 minutes

Step-by-step explanation:

Information given

$n=15$ represent the sample size

$\alpha=0.05$ represent the confidence level

$s^2 =16$ represent the sample variance

$\sigma^2_0 =25$ represent the value that we want to verify

System of hypothesis

We want to test if the true deviation for this case is lesss than 5minutes, so the system of hypothesis would be:

Null Hypothesis: $\sigma^2 \geq 25$

Alternative hypothesis: $\sigma^2$

The statistic is given by:

$\chi^2 =\frac{n-1}{\sigma^2_0} s^2$

And replacing we got:

$\chi^2 =\frac{15-1}{25} 16 =8.96$

The degrees of freedom are given by:

$df = n-1 = 15-1=14$

The p value for this case would be given by:

$p_v =P(\chi^2$

Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not ignificantly lower than 5 minutes

6 0

3 years ago

Eric’s average income for the first 4 months of the year is $1,450.25, what must be his average income for the remaining 8 month

netineya [11]

Too harddd sorryyybxnskzmskndjwjnekkks

6 0

2 years ago

18h 19min 26s<br> + 25h 45min 48s

snow_tiger [21]

Answer:

2 days 5 minuts 14 seconds

Step-by-step explanation:

1 1 1 1 1

18 19 26

+25 45 48

1 24 05 14

4 0

3 years ago