Answer:
Step-by-step explanation:
Help you do what exactly?
Maybe prove that this is not really a valid triangle?
Easily done if we ASSUME that dimension 5 and 4 are valid, the third side of that triangle would be √(5² - 4²) = 3
Which means the other triangle would have legs of 9 and 12 - 3 = 9 making it an equilateral triangle not a right triangle.
If we assume sides 12 and height 4 are correct, then
A = ½(12)(4) = 24 units²
If we ASSUME that the outside legs are true, the the true height can be found using
√(5² - h²) + √(9² - h²) = 12
which resolves to about
h = 3.399
The area would be
A = ½(12)(3.399) = 20.394 units²
A VERRRY confusing question.
