We must mix 240 liters of the 51 % solution and 10 liters of the 26 % solutions to produce 250 liters of 50 % solution.
<h3>How to prepare a solution by using weighted averages</h3>
Herein we have to prepare a solution with fertilizers by mixing two <em>different</em> solutions. The amount needed of the 51 % solution can be found by weighted averages:
(50/100) · (250 L) = (51/100) · x + (26/100) · (250 - x)
50 · 250 = 51 · x + 26 · 250 - 26 · x
24 · 250 = 25 · x
x = 240
We must mix 240 liters of the 51 % solution and 10 liters of the 26 % solutions to produce 250 liters of 50 % solution.
To learn more on weighted averages: brainly.com/question/18554478
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Answer:b
Step-by-step explanation:on edge2020
Answer:
nope
Step-by-step explanation:
they do not have the same exponent
no matter what the number with the x is, as long as the x's have the same exponent, they can be combined...
but in this problem such is not the case, because one x is to the power of 2 and the other is to the power of 1...
so, not in this problem...
We have that
<span>x+5/ [(x+6)(x-1)]
we know that
</span><span>the denominator can not be zero
</span>so
(x+6)(x-1)=0
x+6=0-----> x=-6
x-1=0----> x=1
<span>the appropriate restrictions for the variable are
x=-6
and
x=1
the answer is
x=-6
x=1</span>
Answer:
(9 x - 7 y) (9 x + 7 y)
Step-by-step explanation:
Factor the following:
81 x^2 - 49 y^2
Hint: | Express 81 x^2 - 49 y^2 as a difference of squares.
81 x^2 - 49 y^2 = (9 x)^2 - (7 y)^2:
(9 x)^2 - (7 y)^2
Hint: | Factor the difference of two squares.
Factor the difference of two squares. (9 x)^2 - (7 y)^2 = (9 x - 7 y) (9 x + 7 y):
Answer: (9 x - 7 y) (9 x + 7 y)