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Maurinko [17]
3 years ago
12

Solve 9x + 3y = 15 for y.

Mathematics
2 answers:
igomit [66]3 years ago
8 0

Answer:

D. y = -3x + 5

Step-by-step explanation:

Subtract 9x from both sides

3y = 15 - 9x

y = 15/3 - 9x/3

y = 5 - 3x

y = -3x + 5

Olenka [21]3 years ago
4 0

Answer: D) y = -3x + 5

Step-by-step explanation:

Move x.

3y = -9x + 15

Divide by 3.

y = -3x + 5

Hope it helps :) and let me know if you want me to elaborate.

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3x - 2y + z =-11<br>3y +22=-3<br>32=-9​
mario62 [17]

Answer:

Yes!

Step-by-step explanation:

Correct

8 0
4 years ago
If x=1+√2, evaluate x³+1/x³.
aleksandr82 [10.1K]

Answer:

10√2

Step-by-step explanation:

If x=1+√2, evaluate x³+1/x³

--------

  • x³+1/x³= (x+1/x)(x²-x*1/x+1/x²)=(x+1/x)(x²+1/x²+2-3)= (x+1/x)((x+1/x)²-3)
  • x+1/x= 1+√2 + 1/(1+√2)= 1+√2+(1-√2)/(1-√2)(1+√2)= 1+√2 - (1-√2)= 2√2
  • x³+1/x³= 2√2((2√2)²-3)= 2√2(8-3)= 10√2
3 0
3 years ago
PLEASE HELP 100 POINTS!
krok68 [10]

Answer:

800%

Step-by-step explanation:

<u>Volume of a square based pyramid</u>

\sf V=\dfrac{1}{3}a^2h

where:

  • a = base side length
  • h = height

<u>Given values</u> for Pyramid A:

  • a = 14 inches
  • h = 6 inches

Substitute the given values into the formula to find the volume of <u>Pyramid A</u>:

\begin{aligned}\textsf{Volume of Pyramid A} & = \sf \dfrac{1}{3}(14)^2(6)\\\\& = \sf \dfrac{1176}{3}\\\\& = \sf 392\:\: in^3 \end{aligned}

Given:

  • Volume of Pyramid B = 3136 in³

To find how many times bigger Pyramid B is than Pyramid A, divide the <u>volume of Pyramid B</u> by the <u>volume of Pyramid A</u>:

\implies \sf \dfrac{3136}{392}=8

Therefore, the volume of Pyramid B is 8 times bigger than the volume of Pyramid A.

8 as a percentage is 800%, since 800/100 = 8.

Therefore, the volume of Pyramid B is 800% the volume of Pyramid A.

To verify this, find 800% of the volume of Pyramid A:

⇒ 800% of 392

= 800/100 × 392

= 8 × 392

= 3136

8 0
2 years ago
Plz Help ASAP Must be simplified
Goshia [24]

Answer:

cos (s)

Step-by-step explanation:

3 0
3 years ago
Could someone help me please!?!
crimeas [40]
You can use the Pythagorean Theorem to find the length of the third side AB (Identified as "x" in the figure attached in the problem), which says that in a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of the legs:

 a² = b²+c²

 As we can see the figure, the triangle does not have an angle of 90°, but it can be divided into two equal parts, leaving two triangles with a right angle. We already have the values of the hypotenuse and a leg in triangle "A" , so we can find the value of the other leg:

 b = √(a²-c²) b = √(10²-4²)
 b = 9.16

 With these values, we can find the hypotenuse in the triangle "B":
 x = √b²+c²
 x = √(9.16)²+(4)²
 x = 10

8 0
4 years ago
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