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frutty [35]
3 years ago
5

What is the value of n in this equation?

Mathematics
2 answers:
Tamiku [17]3 years ago
5 0

Answer:

hope it helps you.......

shusha [124]3 years ago
5 0
Hello! I hope it helps :DD Feel free to ask questions if you don’t understand :)

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The area of a certain desert desert one is five times the area of another desert desert 2 if the sum of their areas is 24, 000,
sweet-ann [11.9K]

4,000,000 and 20,000,000 miles²

let x be the area of one desert then 5x is the area of the other

sum = x + 5x = 24,000,000

6x = 24,000,000

divide both sides by 6

x = 4,000,000

one desert is 4,000,000 miles²

and the other is (5 × 4,000,000)= 20,000,000 miles²


8 0
4 years ago
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25 Points. Please help me out. This is the second to last question I need for the night and then I can go to sleep.
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Combine like terms.

4x^3 -6x^3= -2x^3
-8x^2 +2x^2= -6x^2

Answer = -2x^3 -6x^2 +4
4 0
3 years ago
What is 19.7-6.8 the answer
kenny6666 [7]
Hi! :) 19.7 - 6.8 is 12.9. If you need anymore help, ask me!
5 0
4 years ago
Read 2 more answers
Drew jumped farther than all 4 students above but jumped shorter than 7 feet , 7 inches. How far could drew have jumped? Write s
S_A_V [24]
<h3>The distance covered by Drew in long jump is either 7 ft 5 inches OR 7 ft  6 inches.</h3>

Step-by-step explanation:

Here, the needed table is attached for the reference.

Now, as we can see from the table:

The distance covered by  Cindy  = 2 yards, 1 foot 3 inches

The distance covered by  Tyrette   =  7 feet, 2 inches

The distance covered by Nina   =   2 yards, 1 foot, 1 inch

The distance covered by  Monique   = 7 feet, 4 inches

As we know : 1 yard  =  3 feet

So, the distance covered  by :

Cindy  =  2 yards, 1 foot 3 inches = 3 ft x (2)  + 1 ft +  3 in  = 7 ft 3 in

Tyrette   =  7 feet, 2 inches

Nina   =   2 yards, 1 foot, 1 inch  = = 3 ft x (2)  + 1 ft +  1 in  = 7 ft 1 in

Monique   = 7 feet, 4 inches

So by comparing all distances, we can see that:

The maximum distances jumped by all four  is 7 ft 4 inches.

The distance covered by Drew is less than 7 ft 7 in.

So, he must have jumped 7 ft 5 inches OR 7 ft  6 inches.

Hence, the distance covered by Drew in long jump is either 7 ft 5 inches OR 7 ft  6 inches.

4 0
4 years ago
The weight of laboratory grasshoppers follows a Normal distribution, with a mean of 90 grams and a standard deviation of 2 grams
JulsSmile [24]

Answer:

95.44% of the grasshoppers weigh between 86 grams and 94 grams.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 90 grams and a standard deviation of 2 grams.

This means that \mu = 90, \sigma = 2

What percentage of the grasshoppers weigh between 86 grams and 94 grams?

The proportion is the p-value of Z when X = 94 subtracted by the p-value of Z when X = 86. So

X = 94

Z = \frac{X - \mu}{\sigma}

Z = \frac{94 - 90}{2}

Z = 2

Z = 2 has a p-value of 0.9772.

X = 86

Z = \frac{X - \mu}{\sigma}

Z = \frac{86 - 90}{2}

Z = -2

Z = -2 has a p-value of 0.0228.

0.9772 - 0.0228 = 0.9544

0.9544*100% = 95.44%

95.44% of the grasshoppers weigh between 86 grams and 94 grams.

5 0
3 years ago
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