Answer:
See explanation
Step-by-step explanation:
Triangle ABC ha vertices at: A(-3,6), B(0,-4) and (2,6).
Let us apply 90 degrees clockwise about the origin twice to obtain 180 degrees clockwise rotation.
We apply the 90 degrees clockwise rotation rule.




We apply the 90 degrees clockwise rotation rule again on the resulting points:



Let us now apply 90 degrees counterclockwise rotation about the origin twice to obtain 180 degrees counterclockwise rotation.
We apply the 90 degrees counterclockwise rotation rule.




We apply the 90 degrees counterclockwise rotation rule again on the resulting points:



We can see that A''(3,-6), B''(0,-4) and C''(-2,-6) is the same for both the 180 degrees clockwise and counterclockwise rotations.
Draw a circle, then take and draw lines across it for however many you want. circles have infinite lines of symmetry so anything works.
The square root of 2 is irrational. Because 2 is not a perfect square therefore the square root of 2 must be irrational. 1.4 is its approximate to the tenths place. I hope this was helpful
The line has a slope of -6 and a y intercept of 7.
The linear equation is given by:
y = mx + b;
where m is the slope of the line, b is the y intercept, y, x are variables.
The equation of the line passing through the points (6.-29) and (-4,31) is:

Hence the line has a slope of -6 and a y intercept of 7.
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