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galina1969 [7]
3 years ago
8

Comparing fractions with different denominators

Mathematics
1 answer:
tiny-mole [99]3 years ago
3 0
2/3 > 5/6
2/3 > 3/4
hope this helped
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What is the probabililty of getting heads when a coin and getting a number greater than or equal to 4 when rolling a single die
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1/2 on both die, and coin
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3 years ago
Two straight lengths of wire are placed on the ground, forming vertical angles. If the measure of one of the angles formed is 72
lord [1]

One of the other angles is 72. Vertically opposite angles are equal.

Two angles that are side by side on this arrangement are supplementary.

That means they are to 180

x + 72 = 180

x = 180 - 72

x = 108

Answer

the for angles are

72 + 72 + 108 +  108

5 0
3 years ago
Please help with this only
Vitek1552 [10]

I'm going to say b because it wouldn't switch to 91 and it didn't the 4/3 would stay the same

6 0
4 years ago
What is the measure of ABC?
Norma-Jean [14]

Answer:

C. 60

Step-by-step explanation:

You can take away 120 instantly because that angle is acute. This leaves you with A, B, and C. It's most certainly too big to be C. By this point you can look at it and draw a 90 degree angle in your mind and you can see that it looks about 2/3 of a 90 degree angle.

May I have brainliest please? :)

3 0
3 years ago
A ship leaves the port of Miami with a bearing of S80°E and a speed of 15 knots. After 1 hour, the ship turns 90° toward the sou
CaHeK987 [17]

Answer:

The bearing is N 55.62° W

Step-by-step explanation:

ship leaves the port of Miami with a bearing of S80°E and a speed of 15 knots.

It then turns 90° towards the south after one hour.

Still maintain the same speed and direction for two hours.

The bearing is just the angle difference from the ship current location to where it started.

Let the speed be km/h

Distance covered in the first round

= 15*1

= 15km

Distance covered in the second round

=15*2

= 30 km

Angle at C = (90-80)+90

Angle at C = 10+90= 100

Let the distance between the port and the ship be c

C²= a² + b² -2abcos

C²= 15²+30²-2(15)(30)cos 100

C²= 225+900+156.28

C²= 1281.28

C= 35.8 km

Using sine formula

30/sin x= 35.8/sin 100

30/35.8 * sin 100 = sinx

0.838*0.9848= sin x

0.8253= sin x

Sin ^-1 0.8253 = x

55.62° = x

The bearing is N 55.62° W

8 0
3 years ago
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