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11Alexandr11 [23.1K]
2 years ago
9

What will be the output of “AAAAMMMMMHHHVV” using a file compression technique?

Computers and Technology
2 answers:
maw [93]2 years ago
7 0

Answer:

4A5M3H2V

Explanation:

Compression techniques deal with removing <em>redundancy</em> in data to save memory space in computers.

In this case, there are <em>runs</em> of four A's, five M's, three H's and two V's, which is clear that each letter is repeated by some value. That is, there is redundancy in data: some values appear more than once.

Well, to save memory space in a computer, instead of having 4 + 5 + 3 +2 = 14 characters, we can reorder that by having only eight characters (4A5M3H2V), <em>saving the same information</em> using less memory space in a computer.

The former technique has a name. It is called <em>Run-length encoding</em>, and it is one of the most rudimentary compression techniques (Shotts, 2019) and also a <em>lossless</em> <em>compression technique</em>, that is, no data information is lost after the compression process.

stiks02 [169]2 years ago
3 0

I think AAAAMMMMMHHVVV

i think suppose to be 3 v's

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Answer:

  1. public class FindDuplicate{
  2.    public static void main(String[] args) {
  3.        Scanner input = new Scanner(System.in);
  4.        int n = 5;
  5.        int arr[] = new int[n];
  6.        for(int i=0; i < arr.length; i++){
  7.            int inputNum = input.nextInt();
  8.            if(inputNum >=1 && inputNum <=n) {
  9.                arr[i] = inputNum;
  10.            }
  11.        }
  12.        for(int j =0; j < arr.length; j++){
  13.            for(int k = 0; k < arr.length; k++){
  14.                if(j == k){
  15.                    continue;
  16.                }else{
  17.                    if(arr[j] == arr[k]){
  18.                        System.out.println("True");
  19.                        return;
  20.                    }
  21.                }
  22.            }
  23.        }
  24.        System.out.println("False");
  25.    }
  26. }

Explanation:

Firstly, create a Scanner object to get user input (Line 4).

Next, create an array with n-size (Line 7) and then create a for-loop to get user repeatedly enter an integer and assign the input value to the array (Line 9 - 14).

Next, create a double layer for-loop to check the each element in the array against the other elements to see if there is any duplication detected and display "True" (Line 21 - 22). If duplication is found the program will display True and terminate the whole program using return (Line 23). The condition set in Line 18 is to ensure the comparison is not between the same element.

If all the elements in the array are unique the if block (Line 21 - 23) won't run and it will proceed to Line 28 to display message "False".

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