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3 years ago

What will be the output of “AAAAMMMMMHHHVV” using a file compression technique?

Computers and Technology

2 answers:

maw [93]3 years ago

7 0

Answer:

4A5M3H2V

Explanation:

Compression techniques deal with removing redundancy in data to save memory space in computers.

In this case, there are runs of four A's, five M's, three H's and two V's, which is clear that each letter is repeated by some value. That is, there is redundancy in data: some values appear more than once.

Well, to save memory space in a computer, instead of having 4 + 5 + 3 +2 = 14 characters, we can reorder that by having only eight characters (4A5M3H2V), saving the same information using less memory space in a computer.

The former technique has a name. It is called Run-length encoding, and it is one of the most rudimentary compression techniques (Shotts, 2019) and also a lossless compression technique, that is, no data information is lost after the compression process.

stiks02 [169]3 years ago

3 0

I think AAAAMMMMMHHVVV

i think suppose to be 3 v's

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Answer:

#include <iostream>

#include <time.h>

#include <string>

using namespace std;

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srand(time(NULL));

cout<<"Throw dice"<<endl;

int b =0;

int a=0;

a=rand()%6;

b=rand()%6;

for (int i =0;i<1;i++)

{cout<<"dice one: "<<a<<endl;}

for (int i =0;i<1;i++)

{cout<<"dice two: "<<b<<endl;}

if(a>b)

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if(b>a)

{cout<<"second dice won"<<endl;}

else{cout<<"they are same"<<endl;

return main();

}

return 0;

}

Explanation:

/*maybe it help you it is almost done*/

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Lubov Fominskaja [6]

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Explanation:

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3 years ago

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xxTIMURxx [149]

Answer:

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Explanation:

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3 years ago

Plz can someone tell me the answers ?

Ganezh [65]

Answer:

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Explanation:

you can

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using a for loop, write a program that prints out the decimal equivalents of 1/2, 1/3, 1/4,..., 1/10.

ValentinkaMS [17]

In python:

##Specifies the range that the variable 'number' should change within
for number in range(2,10):
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print(1 / number)

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3 years ago