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Korolek [52]
3 years ago
13

Does anyone have a budget pc parts list for GAMING

Computers and Technology
1 answer:
Afina-wow [57]3 years ago
6 0

Answer:

It’s in the following image my friend :)

Explanation:

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Write a function in python that computes and returns the sum of the digits for any integer that is between 1 and 999, inclusive.
DanielleElmas [232]

Answer:

def sum_digits(number):

   total = 0

   if 1 <= number <= 999:

       while number > 0:

           r = int (number % 10)

           total +=r

           number /= 10

   else:

       return -1

   return total

   

print(sum_digits(658))

Explanation:

Write a function named sum_digits that takes one parameter, number

Check if the number is between 1 and 999. If it is, create a while loop that iterates until number is greater than 0. Get the last digit of the number using mudulo and add it to the total. Then, divide the number by 10 to move to the next digit. This process will continue until the number is equal to 0.

If the number is not in the given range, return -1, indicating invalid range.

Call the function and print the result

3 0
3 years ago
What is the main advantage of using a WYSIWYG("what you see is what you get")editor when constructing a website
Tomtit [17]

Answer:

c

12121212121212121212121212121221212121212121212

7 0
3 years ago
How much cell phone data does the average person use a month
azamat
It all depends on what you're doing online.
7 0
3 years ago
Consider the following method, remDups, which is intended to remove duplicate consecutive elements from nums, an ArrayList of in
MAXImum [283]

Answer:

B. {1, 2, 2, 3, 3, 4, 5}

Explanation:

Given

The above code segment

Required

Determine which list does not work

The list that didn't work is B.\ \{1, 2, 2, 3, 3, 4, 5\}

Considering options (A) to (E), we notice that only list B has consecutive duplicate numbers i.e. 2,2 and 3,3

All other list do not have consecutive duplicate numbers

Option B can be represented as:

nums[0] = 1

nums[1] = 2

nums[2] = 2

nums[3] = 3

nums[4] = 3

nums[5] = 4

nums[6] = 5

if (nums.get(j).equals(nums.get(j + 1)))

The above if condition checks for duplicate numbers.

In (B), when the elements at index 1 and 2 (i.e. 2 and 2) are compared, one of the 2's is removed and the Arraylist becomes:

nums[0] = 1

nums[1] = 2

nums[2] = 3

nums[3] = 3

nums[4] = 4

nums[5] = 5

The next comparison is: index 3 and 4. Meaning that comparison of index 2 and 3 has been skipped.

<em>This is so because of the way the if statement is constructed.</em>

3 0
3 years ago
Is Bob Lazar telling a lie/withholding information?
Anon25 [30]

Answer:

I think he may be a nut, but I'm not sure, there's little evidence of what he says to be true.

6 0
4 years ago
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